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julsineya [31]
2 years ago
7

The partial pressure of a gas is a inversely proportional to the temperature of the gas. b. directly proportional to the volume

of the gas. c. always constant during a chemical reaction. d. directly proportional to the number of moles of the gas. e. proportional to the gas constant, R.
Chemistry
1 answer:
vlabodo [156]2 years ago
3 0

Answer:

d. directly proportional to the number of moles of the gas.

Explanation:

The formula for the partial pressure of a gas is written as -

P = n * P ( total )

P = partial pressure of the gas ,

n = mole fraction of the gas ,

P ( total ) = Total pressure of the mixture of gas .

Hence , from the above equation ,

the partial pressure is directly proportional to the mole fraction , i.e. , on increasing the number of moles of gas , the partial pressure increases .

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a solid with a low melting point is most likely what? A.ionic B. covalent C. metallic or D. None of the above.
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3 0
3 years ago
What is the pH of a KOH solution that has [H ] = 1. 87 × 10–13 M? What is the pOH of a KOH solution that has [OH− ] = 5. 81 × 10
vlada-n [284]

pH is the hydrogen ion concentration and pOH is the hydroxide ion concentration in the solution. pH KOH is 12.73, pOH KOH is 2.24 and pH NaCl is 7.

<h3>What are pH and pOH?</h3>

pH is the negative log of the hydrogen ion concentration and pOH is the negative log of the hydroxide ion concentration.

The relation between the pH and pOH can be given as, \rm pOH = 14 - pH

The pH of KOH can be calculated by the formula,

\rm pH = \rm -log [H^{+}]

In the first case, the concentration of the KOH is 1. 87 \times  10^{-13}\;\rm  M

Substituting values in the equation:

\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 87 \times  10^{-13}\;\rm  M ]\\\\&= 12.73\end{aligned}

Hence, the pH of KOH is 12.73.

<u />

pOH of KOH can be calculated by the formula,

\rm pOH = \rm -log [OH^{-}]

The hydroxide concentration of the KOH solution is 5. 81 \times 10^{-3}\;\rm  M

Substituting value in the equation:

\begin{aligned} \rm pOH &= \rm -log [OH^{-}]\\\\&= \rm -log [5. 81 \times 10^{-3}\;\rm  M ]\\\\&= 2.24 \end{aligned}

Hence, the pOH of KOH is 2.24

<u />

The pH of NaCl can be calculated by the formula,

\rm pH = \rm -log [H^{+}]

In the third case, the concentration of the NaCl is 1. 00\times 10^{-7}\;\rm  M

Substituting values in the equation:

\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 00 \times  10^{-7}\;\rm  M ]\\\\&= 7 \end{aligned}

Hence, the pH of KOH is 7.0.

Therefore, KOH is basic and NaCl is approximately neutral.

Learn more about pH and pOH here:

brainly.com/question/13885794

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2 years ago
II need this asap !!!!!!!
Xelga [282]

Answer:

1. B.10 mol/l

2. D.

3.A.

Explanation:

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