<span>The high-energy electron travels down an electron transport chain, losing energy as it goes.
Some of the released energy drives pumping of </span><span><span>\text H^+<span>H<span><span>+</span><span></span></span></span></span>H, start superscript, plus, end superscript</span><span> ions from the stroma into the thylakoid interior, building a gradient.
</span><span><span>H^+<span>H<span><span>+</span><span></span></span></span></span>H, start superscript, plus, end superscript</span><span> ions from the splitting of water also add to the gradient.
</span><span><span> H^+<span>H<span><span>+</span><span></span></span></span></span>H, start superscript, plus, end superscript</span><span> ions flow down their gradient and into the stroma, they pass through ATP synthase, driving ATP production in a process known as </span>chemiosmosis<span>.</span>
Answer:
The Net reaction is
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-

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Explanation:
From the Question we are told that the buffers are
and 
When NaOH is added the Net ionic reaction would be
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-

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<u>Answer:</u> The concentration of solution is 0.342 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:

We are given:
Mass of solute (Sodium chloride) = 15 g
Molar mass of sodium chloride = 58.5 g/mol
Volume of solution = 750 mL
Putting values in above equation, we get:

Hence, the concentration of solution is 0.342 M
Answer:
B .it is an exothermic reaction
Explanation:
i need brainleyest
Answer:
T₂ = 150 K
Explanation:
Given data:
Initial volume of gas = 804 mL
Initial temperature = 27°C (27+273=300 K)
Final temperature = ?
Final volume = 402 mL
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = V₂T₁/V₁
T₂ = 402 mL × 300 K / 804 mL
T₂ = 120,600 mL.K / 804 mL
T₂ = 150 K