- <span>A </span>projectile<span> is </span>thrown upward so<span> that </span>its distance above<span> the </span>ground after t seconds<span> is </span>given<span> by the </span>function h(t<span>) = - 16t² + </span>640t<span>. </span>After<span> how </span>many seconds<span> does the </span>projectile<span>take</span><span> to reach </span>its<span> maximum height? I made the </span>function<span> .</span>
Answer:
B y = (-7/4)x - 7
Step-by-step explanation:
Slope intercept form is
y = mx + b
Where m is the slope and b is the y-intercept
m = rise/run
m = ∆y/∆x
m = (y₂ - y₁) / (x₂ - x₁)
m = (-7 - 0) / (0 - -4)
m = -7/4
From the graph the y-intercept
b = -7
-------------------------
y = (-7/4)x - 7
B is the answer
harry styles loves you bruv <3
Answer: 39s(9s-5)
Step-by-step explanation:
(3s*13) (9s-5)
remove the parenthesis ex: (a)=a
3s*13 (9s-5)
Multiply the numbers
39s(9s-5)
