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murzikaleks [220]
3 years ago
11

Compare and contrast endocytosis and exocytosis. please help!!!

Biology
1 answer:
Dmitry [639]3 years ago
7 0
Endocytosis is the process of capturing a substance or particle from outside the cell by engulfing it with the cell membrane, and bringing it into the cell. Exocytosis describes the process of vesicles fusing with the plasma membrane and releasing their contents to the outside of the cell. The main similarity is that both exocytosis and endocytosis are involved in transporting big molecules across the membrane using a vesicle and needs energy. The basic differences are that : 1) Endocytosis brings materials to the inside of the cell while exocytosis takes them out. Exocytosis, on the other hand, is described as the process of fusing vesicles with the plasma membrane to release their contents to the external environment of the cell.
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Which of these species would be most in danger of becoming extinct if one of their food sources became unavailable?
Advocard [28]

Answer:

Due to their being no options (possibly just an incomplete question), I will just give an answer. So for panda bears, if their food sources became unavailable, they would most likely be in danger of becoming extinct.

But one thing is, pandas do have the ability to survive with bamboo.

But since bamboo comprises 99 percent of their food, although they also consume other plants and even meat, I highly doubt they could (whose make the remaining 1 percent ).

Because the gene T1R1 mutated some 4 million years ago, causing them to lose the ability to taste umami, giant pandas have come to rely significantly on bamboo (which is what makes meat tasty for omnivores and carnivores). The availability of bamboo trunks at the time coincided with their purported food source becoming increasingly limited, thus pandas became used to them and began to rely significantly on them, as they do now.

Thank you,

Eddie

7 0
2 years ago
A geneticist crossed fruit flies to determine the phenotypic ratio. The geneticist crossed a fly with blistery wings and spinele
kondor19780726 [428]

Complete question:

A geneticist crossed fruit flies to determine the phenotypic ratio. The geneticist crossed a fly with blistery wings and spineless bristles (bbss) with a heterozygous fly that had normal wings and normal bristles (BbSs). Which proportion of offspring that are dominant for both traits in would you not expect based on Mendel's law of independent assortment? 1/2 , 4/16, 25% , or 1/4

Answer:

1/2 is the proportion of the offspring that is NOT expected among individuals that are dominant for both traits.

4/16 = 1/4 = 25% of the progeny and the correct expected proportion of individuals that are dominant for both traits.

Explanation:

<u>Available data</u>:

  • Cross:  a fly with blistery wings and spineless bristles with a heterozygous fly that had normal wings and normal bristles
  • Recessive trait: blistery wings and spineless bristles
  • Dominant trait: normal wings and normal bristles

Let us say that:

  • B is the dominant allele for normal wings
  • b is the recessive allele for blistery wings
  • S is the dominant allele for normal bristles
  • s is the recessive allele for spineless bristles

Parentals)        bbss       x        BbSs

Gametes)  bs, bs, bs, bs     BS, Bs, bS, bs

Punnett square)    BS        Bs         bS        bs

                     bs    BbSs    Bbss     bbSs    bbss

                     bs    BbSs    Bbss     bbSs    bbss

                     bs    BbSs    Bbss     bbSs    bbss

                     bs    BbSs    Bbss     bbSs    bbss

F1)  4/16 = 1/4 = 25%  of the progeny is expected to be BbSs, dyhibrid individuals, expressing normal wings and normal bristles

     4/16 = 1/4 = 25% of the progeny is expected to be Bbss, expressing normal wings and spineless bristles

     4/16 = 1/4 = 25% of the progeny is expected to be bbSs, expressing  blistery wings and normal bristles

     4/16 = 1/4 = 25% of the progeny is expected to be bbss, expressing  blistery wings and spineless bristles    

5 0
3 years ago
In humans, attached earlobes are recessive to free hanging earlobs. If two heterozygous free lobed parents mate, what is the cha
scoundrel [369]
Bellow I attached the punnet square you need. From it you can see, that the likelihood of producing an offspring with attached earlobes is 25% (ff)

7 0
3 years ago
Rosa drew a flow chart of the carbon cycle. Flow chart of the carbon cycle with 4 boxes connected by arrows. Box 1: carbon dioxi
leonid [27]

Answer:

(a) X: Producers undergo photosynthesis. Y: Decomposers return carbon to the soil and release waste.

Explanation:

<em>(a) X: Producers undergo photosynthesis. Y: Decomposers return carbon to the soil and release waste. </em>

<em>(b) X: Decomposers return carbon to the soil and release waste. Y: Producers undergo photosynthesis. </em>

<em>(c) X: Decomposers take in carbon dioxide. Y: Producers absorb carbon through their roots. </em>

<em>(d)X: Producers absorb carbon through their roots. Y: Decomposers take in carbon dioxide. </em>

<u>Box 2 (X)  would be the process through which producers fix carbon dioxide to produce their own food, the carbohydrate. T</u>he process is otherwise known as photosynthesis and can be represented by the following equation:

6CO_2 + 6H_20 --> C_6H_1_2O_6 + 6O_2

<u>Box 4 (Y) would be the process of decomposition.</u> Both producers and consumers eventually die and decompose in the soil. During this process, some of the carbon returns to the soil as organic matters while the process of microbial decomposition releases carbon dioxide into the atmosphere.

The correct option would be (a).

3 0
3 years ago
How did Mendel discover that the blending theory of<br> inheritance was incorrect using pea plants?
mariarad [96]

Answer:

Mendel disproved the blending theory of genetics when he cross pollinated tall and short pea plants and the offspring were either tall or short, not medium like the blending theory of genetics suggests.

Explanation:

4 0
3 years ago
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