Question

The proof that ΔACB ≅ ΔECD is shown. Given: AE and DB bisect each other at C. Prove: ΔACB ≅ ΔECD Triangles A B C and C D E share common point C. A flow chart has 5 boxes with arrows facing downward connecting the boxes. Each of the boxes are labeled. Box 1 contains line segment A E and line segment B E bisect each other at C and is labeled given. Box 2 contains line segment A C is-congruent-to line segment E C and is labeled definition of bisector. Box 3 contains question mark and is labeled vertical angles theorem. Box 4 contains line segment D C is-congruent-to line segment B C and is labeled definition of bisector. Box 5 contains triangle A C B is-congruent-to triangle E C D and is labeled SAS. What is the missing statement in the proof? ∠BAC ≅ ∠DEC ∠ACD ≅ ∠ECB ∠ACB ≅ ∠ECD ∠BCA ≅ ∠DCA

Answer 1

Answer:

i hope this is right but im pretty sure its ∠ACB ≅ ∠ECD

Step-by-step explanation:

Answer 2

Answer:

good work

Step-by-step explanation:

high