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Ksivusya [100]
3 years ago
11

Factor 4x2-100 completely

Mathematics
1 answer:
expeople1 [14]3 years ago
5 0
You just have to use the squares one to factor this and this is what I got.

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Your friend claims that when a polynomial function has a leading coeffcient of 1 and the coefficients are all integers , every p
sammy [17]

Using the rational root theorem, it is found that your friend is correct.

<h3>What is the rational root theorem?</h3>
  • It is a theorem that states that for a polynomial with integer coefficients, with q being the factors of the leading coefficient and p being the factors of the constant, every <u>possible rational root</u> is the format \frac{p}{q}.

In this problem:

  • The leading coefficient is 1, hence it's only factor is q = 1, thus guaranteeing that every possible rational zero is an integer, which means that your friend is correct.

To learn more about the rational root theorem, you can take a look at brainly.com/question/10937559

8 0
2 years ago
What ia the common ratio of the sequence? -2 , 6, -18, 54,...
Jlenok [28]
Its a multiplication by -3 on each term, so I think you're gonna answer is by r=-3, maybe?
7 0
3 years ago
What is the greatest common factor of 31 43 and 95?
kramer
It’s 1. Apparently my answer is not long enough so I’m making it longer :(:
7 0
3 years ago
1 1 11<br> - + - + -<br> 4 3 12 = ????
Temka [501]

Answer:

What?

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
30 years ago zoe was 2/3 as old as luke, 18 years ago zoe was 5/6 as old as luke how old are they now
barxatty [35]

Based on the mathematical statements, Zoe is 56 years old and Luke is 66 years old, now

<h3>How to determine how old they are now?</h3>

From the question, we have the following statements that can be used in our computation:

<u>30 years ago</u>

Zoe was 2/3 as old as Luke

<u>18 years ago</u>

Zoe was 5/6 as old as Luke

Let their present ages be represented as

Zoe = x

Luke = y

So, we have the following representations

<u>30 years ago</u>

Zoe was 2/3 as old as Luke

x - 36 = 2/3(y - 36)

<u>18 years ago</u>

Zoe was 5/6 as old as Luke

x - 18 = 5/6(y - 18)

So, we have the following system of equations

x - 36 = 2/3(y - 36)

x - 18 = 5/6(y - 18)

Make x the subject in x - 18 = 5/6(y - 18)

x = 5/6(y - 18) + 16

Substitute x = 5/6(y - 18) + 16 in x - 36 = 2/3(y - 36)

5/6(y - 18) + 16 - 36 = 2/3(y - 36)

Open the brackets

5/6y - 15 + 16 - 36 = 2/3y - 24

Evaluate the like terms

5/6y - 35 = 2/3y - 24

Multiply through by 6

5y - 210 = 4y - 144

Evaluate the like terms

y = 66

Substitute y = 66 in x = 5/6(y - 18) + 16

x = 5/6(66 - 18) + 16

Evaluate

x = 56

Recall that

Zoe = x

Luke = y

So, we have

Zoe = x = 56

Luke = y = 66

Hence, they are 56 and 66 years, now

Read more about equations at

brainly.com/question/2476251

#SPJ1

5 0
10 months ago
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