Answer:
log3 (500)
Step-by-step explanation:
3 log3 (5) * log3(4)
We know that a log b(c) = log b(c^a)
log3 (5)^3 * log3(4)
We know that log a(b) * log a (c) = loga( b*c)
log3 ((5)^3 * 4)
log3 (125*4)
log3 (500)
3.15 /7 = 0.45
3.20/8 = 0.40
4.10/10 = 0.41
4.80/16 = 0.3
Answer is 1. 7 stamps worth 3.15
Answer:
Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0
Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0
Here to test Fertilizer A height is greater than Fertilizer B
Two Sample T Test:
t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}
Where S_p^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}
S_p^2=\frac{(14)0.25^2+(12)0.2^2}{15+13-2}= 0.0521154
t=\frac{12.92-12.63}{\sqrt{0.0521154(1/15+1/13)}}= 3.3524
P value for Test Statistic of P(3.3524,26) = 0.0012
df = n1+n2-2 = 26
Critical value of P : t_{0.025,26}=2.05553
We can conclude that Test statistic is significant. Sufficient evidence to prove that we can Reject Null hypothesis and can say Fertilizer A is greater than Fertilizer B.
I believe (3) hope it’s correct :)
The answer is B. -3, 3
This is why:
3|3*3| = 27
3|9| = 27
3*9 = 27
The same will happen with -3 since this | means the distance from the number to zero and in this case it is 3 units til you reach zero. So the answer is B. 3, -3
