Welp. I sure hope you like the Pythagorean theorem...
Top line:
One point is (-2,-2) while the other is (3,-3)
Thus the distance in between is sqrt((3-(-2))^2+(-3-(-2))^2)=sqrt(5^2+(-1)^2)=sqrt(26)
Most right line:
One point is (4,-6) while the other is (3,-3)
Thus the distance in between is sqrt((3-4)^2+(-3-(-6))^2)=sqrt((-1)^2+3^2)=sqrt(10)
Most bottom line:
One point is (1,-6) while the other is (4,-6)
Thus the distance in between is sqrt(4-1)^2+(-6-(-6))^2)=sqrt(3^2+0^2)=sqrt(9)=3
Most bottom left line:
One point is (1,-6) while the other is (-2,-4)
Thus the distance in between is sqrt((1-(-2))^2+(-6-(-4))^2)=sqrt(3^2+(-2)^2)=sqrt(13)
Lastly the most left line:
One point is (-2,-2) while the other is (-2,-4)
Thus the distance in between is sqrt((-2-(-2))^2+(-2-(-4))^2)=sqrt(0^2+(2)^2)=sqrt(4)=2
Thus to find the perimeter, we add up all the sides to get
sqrt(26)+sqrt(10)+3+sqrt(13)+2=16.8668 or B
Answer:
First image: -83/2
Second image: 8.62%
Third image: -43/2
Step-by-step explanation:
See the attachments
10.3 = 0.6y...divide both sides by 0.6
10.3 / 0.6 = y
17.17 = y <=
Answer: 3
Step-by-step explanation:
You can answer this question by using the equation
(8+x)(7+x)=110
The x represents the width, as we do not know the area. If you simplify the equation, it becomes 56+15x+x2=110.
If you move all the terms to the left side, and rearrange it, it can become x^2+15x-54=0
This can be simplified into (x-3)(x+18)=0
This equation makes it so that x is either 3 or -18. It is not possible for a width to be -18, so the width must be 3.