6 runners, 3 medals, how many ways to give them? well, runner say 2 could get gold or not, bronze or not and silver or not, and so can any other runnner, and the order "does matter", it makes a distinction, thus, is a Permutation
Ship A receives a distress signal from the southwest, and ship B receives a distress signal from the same vessel from the north.
At what location is the vessel in distress located? Describe how you arrived at your conclusion using complete sentences. You must show all work in order to receive credit.
1 answer:
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Answer:
11). m∠W = 70°
12). m∠M = 95°
13). m∠Q = 135°
14). m∠Q = 55°
15). m∠X = 110°
Step-by-step explanation:
11). m∠W + m∠X = 180° [Consecutive interior angles]
(24x - 2) + (36x + 2) = 180°
60x = 180°
x =
x = 3
Therefore, m∠W = (24x - 2)°
m∠W = (24×3 - 2)
= 72 - 2
= 70°
Since opposite angles of a parallelogram are equal in measure.
m∠Y = m∠W = 70°
12). m∠J + m∠K = 180° [Consecutive interior angles]
(6x + 19) + (8x + 7) = 180°
14x + 26 = 180
14x = 180 - 26
14x = 154
x =
x = 11
m∠K = (8x + 7)
m∠K = 8×11 + 7
m∠K = 95°
Since m∠M = m∠K
Therefore, m∠M = 95°
13). m∠Q = m∠S [Opposite angles of a parallelogram]
x + 135 = 2x + 135
2x - x = 0
x = 0
Therefore, m∠Q = 135°
14). m∠Q = m∠S [Opposite angles of a parallelogram]
14x - 1 = 13x + 3
14x - 13x = 3 + 1
x = 4
m∠Q = (13x + 3)
= 13×4 + 3
= 52 + 3
m∠Q = 55°
15). m∠Z = m∠X
(19x - 4) = (17x + 8)
19x - 17x = 12
2x = 12
x = 6
m∠X = (17x + 8)°
m∠X = 17×6 + 8
m∠X = 110°
Refer to the diagram shown below.
When x = 30 ft, the cable is at 15 ft, therefore y(30) = 15.
That is,
a(30 - h)² + k = 15 (1)
Also, because the distance between the supports is 90 ft, therefore
y(0) = 6 ft, and y(90) = 6 ft
That is,
a(-h)² + k = 6 (2)
a(90 - h)² + k = 6 (3)
From (2) and (3), obtain
a(90 - h)² = ah²
90² - 180h + h² = h²
180h = 90²
h = 45 ft.
From (1) and (2), obtain
225a + k = 15
2025a + k = 6
Therefore
1800a = -9
a = - 0.005
k = 15 - 225(-0.005) = 16.125 ft
Answer:
The equation for the cable is
y = - 0.005(x - 45)² + 16.125
A graph of the solution verifies that the solution is correct.
When x = 30 ft, the cable is at 15 ft, therefore y(30) = 15.
That is,
a(30 - h)² + k = 15 (1)
Also, because the distance between the supports is 90 ft, therefore
y(0) = 6 ft, and y(90) = 6 ft
That is,
a(-h)² + k = 6 (2)
a(90 - h)² + k = 6 (3)
From (2) and (3), obtain
a(90 - h)² = ah²
90² - 180h + h² = h²
180h = 90²
h = 45 ft.
From (1) and (2), obtain
225a + k = 15
2025a + k = 6
Therefore
1800a = -9
a = - 0.005
k = 15 - 225(-0.005) = 16.125 ft
Answer:
The equation for the cable is
y = - 0.005(x - 45)² + 16.125
A graph of the solution verifies that the solution is correct.