Answer:
(B) Write Negative 3 and one-third as Negative StartFraction 10 over 3 EndFraction, and find the reciprocal of StartFraction 4 over 9 EndFraction as StartFraction 9 over 4 EndFraction. Then, rewrite Negative 3 and one-third divided by StartFraction 4 over 9 EndFraction as Negative StartFraction 10 over 3 EndFraction times StartFraction 9 over 4 EndFraction. The quotient is Negative 7 and StartFraction 6 over 12 EndFraction = Negative 7 and one-half.
Step-by-step explanation:
To find the quotient of the division:

Step 1: 

Step 2: Find the reciprocal of 

r = -3/4p - 18/5
(or you could put 3.6 or 3 3/5 instead of 18/5)
2 - 3/4p = 5/6r + 5
-5 -5
-3 - 3/4p = 5/6r
/(5/6) /(5/6)
-18/5 - 3/4p = r
-3/4p - 18/5 = r
Answer:
go where they do school on
Step-by-step explanation:
The most simple form (I'm defining the parabola to be an upwards-opening one) would be
Explanation:
Statements are numbered; reasons are in italics.
1. ABCD is a parallelogram with AB≅CD and BC≅AD. <em>Given; definition of a parallelogram</em>.
2. Diagonal AC ≅ diagonal CA. <em>Reflexive property of congruence</em>.
3. ΔABC ≅ ΔCDA. <em>SSS congruence postulate</em>.
4. ∠B ≅ ∠D. <em>CPCTC</em>. (Opposite angles B and D are congruent.)
5. Diagonal BD ≅ diagonal DB. <em>Reflexive property of congruence</em>.
6. ΔABD ≅ ΔCDB. <em>SSS congruence postulate</em>.
7. ∠A ≅ ∠C. <em>CPCTC</em>. (Opposite angles A and C are congruent.)