Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
Her fastest change in elevation was -200 feet in 10 minutes. She was going at a rate of 20 fpm (feet per minute) compared to 15 fpm.
Answer:
C)
The rate of change/slope is constant, when you calculate it for this problem, it doesn't change for any amount of marbles listed in the table
Answer= 70.7 meters.
Step-by-step explanation:
We have been given that Elise walks diagonally from one corner of a square plaza to another. Each side of the plaza is 50 meters.
Since we know that diagonal of a square is product of side length of square and . So we will find diagonal of our given square plaza by multiplying 50 by .
Therefore, diagonal distance across the plaza is 70.7 meters.
The other commentor is right. The correct answer is 2-i
The second follow-up question is the second option
f(x) = (x<span> – (2 + </span>i))(x<span> – (2 –</span><span> i</span>))(x<span> – 5)
</span>The third follow-up question has these three answers.
9x^2
25x
25
