One solution was found :
x = ∛15 = 2.466
Step by step solution :
Step 1 :
12÷x2
Equation at the end of step 1 :
3 12
(((((3x-————)+6x)-27)-2x)-——)-(6x-27) = 0
(x2) x2
Step 2 :
3÷ x2
Equation at the end of step 2 :
3 12
(((((3x-——)+6x)-27)-2x)-——)-(6x-27) = 0
x2 x2
Answer:
p^2 + q^2 = 22/9.
Step-by-step explanation:
For a quadratic function ax^2 + bx + c if the zeroes are A and B then
A + B = -b/a and AB = c/a.
2x^2 - 7x + 3
Now p and q are the zeroes of the above function so
p + q = 7/3 and pq = 3/2.
Now p^2 + q^2 = (p + q)^2 - 2pq
= (7/3)^2 - 2* 3/2
= 49/9 - 3
= 49/4 - 27/9
= 22/9.
Hi there! It’s gonna be 1
By definition we have to:
A mathematical function is a relationship that is established between two sets, through which each element of the first set is assigned a single element of the second set or none.
The initial set or starting set is also called the domain; the final set or set of arrival, meanwhile, can be called codomain.
We have the following information:
{(-5.2), (-2.5), (0.7), (0.9)}
The data does not represent a function because two different values of the range belong to an element of the domain:
(0.7)
(0.9)
Answer:
The relation is not a function.
Answer:
6x^3-11x^2+14x-5
Step-by-step explanation:
