Remark
At first glance, one would think this problem isn't possible. But if you use the magnifying glass, you see that it is.
Solve
25 carrots puts you somewhere to the left of the shaded area, so C and D are both wrong.
That leaves you with A or B. You need 30 carrots (or just very slightly less) at least to solve this problem. The way to distinguish between A and B is to look at the line that goes from lower right to upper left. When you magnify this graph, you see that at 30 carrots the line or boundary goes through 20 cucumbers. 21 is just very slightly above that and 25 is far above the other line. 21 cucumbers is the only possible right answer for the number of cucumbers. 25 is too high. B is wrong. The answer is A.
The story problem of shawn's poster length and width is the correct one
Answer: 2 19/24 hours was spent in practising.
Step-by-step explanation:
During the first hour, they practiced for 5/8 of an hour. During the second hour, they practiced for 2/3 of an hour. This means that the total time for which they practiced in the first 2 hours would be
5/8 + 2/3 = 31/24 hours
During the last two hours, they first practiced for 3/5 of an hour, took a 1/2 hour break and then practiced the rest of the time. This means that the rest of the time for which they practiced is
2 - (3/5 + 1/2) = 2 - 11/10 = 9/10
Therefore, the time they spent practicing in total would be
31/24 + 3/5 + 9/10 = 67/24 =
2 19/24 hours
I belive its B,and D,
B because, the lines are supplementary(because supplementary means it equal 180 degrees in length, which is those two angles.)
D, because they are put in such an angle in which making them adjecant.
Hope I helped:-) Bye bye.
Answer: 2%
Step-by-step explanation:
Let A be the event of having defective steering and B be the vent of having defective brake linings.
Given: P(A) = 0.03 P(B) = 0.05
P(neither A nor B ) = 0.94
Using formula: P(either A nor B) = 1- P(neither A nor B )
= 1-0.94
i.e. P(either A nor B) =0.06
Using formula:P(A and B) = P(A)+P(B)-P(either A or B)
P(A and B) =0.03+0.05-0.06
= 0.02
Hence, the percentage of the trucks have both defects = 2%
