Two sets (or three technically)
sets {2, 4, 6, 8, 10} & {8,9,10}
The probability of one of the above numbers because it is a union of those two vars/sets so numbers from either set go
{2, 4, 6, 8, 9, 10}
Thats 6 of the 10 numbers
6/10
.6
If i'm wrong, sorry, haven't done this kind of stuff in a while
Answer:
x = -7
Step-by-step explanation:
41 + 76 + x + 70 = 180
x + 187 = 180
x = 180 - 187
x = -7
maybe a? because it’s reflecting off of the x axis
Answer:
Numbers =(6,-2 )
Step-by step explanation:
Given
the sum of two numbers is four and the sum of their squares minus three times their product is 76,
Let the first term =X
Second term will be=4-x
So
X^2+(4-x)^2-3x(4-x)=76
x^2+16+x^2-8x-12x+3x^2=76
5x^2-20x+16=76
5x^2-20x-60=0
5(x^2-4x-12)=0
So x^2-4x-12=0
x^2-(6-2)x-12=0
x^2-6x+2x-12=0
X(x-6)+2(x-6)=0
(X-6)(X+2)=0
X=6,-2
Let X=6 and -2 then numbers will be 6 and (4-6)=-2
