The right system of equations to describe the situation would
be on the form:
x1 = 8000 + y1*t
and
x2 = 8000 + y2*t
where x1 and x2 represents the total money of Imogene and her
friend respectively at the end of t years.
Now for the value of amount earned, y1 and y2:
y1=8000*0.08
y2=2000*√(t-2)
<span> </span>
Answer:
x+30=90
OR
180-120=x
The measure of the angle is 60 degrees.
Step-by-step explanation:
Plug in 60 as x and it will fit each equation.
f(x) = (x - 4)^2 - 1
g(x) = -(1/4) ( x - 4)^2 + 4
both the x and y values have to be the same. Start with the y values
f(x) = g(x)
(x - 4)^2 - 1 = -(1/4) (x - 4)^2 + 4 Add 1 to both sides.
(x - 4)^2 = -(1/4) (x - 4)^2 + 5 Add 1/4(x - 4)^2 to both sides.
(5/4) (x - 4)^2 = 5 Divide by 5/4 on both sides.
(x - 4)^2 = 5//(5/4)
(x - 4)^2 = (5/1)//5/4 Invert the second fraction and multiply
(x - 4)^2 = 5/1 * 4/5
(x - 4)^2 = 4 The 5s cancel
(x - 4)^2 = 4 Take the square root of both sides.
(x - 4) = +/- 2 Add 4 to each answer. Start with +2 on the right.
x - 4 + 4 = 2 + 4
x = 4 + 2 = 6
The x value that makes f(x)- g(x) = 0 is x = 6 The point is (6,3) answer.
Answer C.
================================================
You do not need this next part. It is just for completeness.
x - 4 = - 2
x = 4 -2
x = 2
What are the y values for these 2 x values?
y = (x - 4)^2 - 1
y = (6 - 4)^2 - 1
y = 4 - 1
y = 3
The point where f(x) - g(x) = 0 is (6,3) <<<<<< Answer 1
The second point is
y = (x - 4)^2 - 1
y = (2 - 4)^2 - 1
y = (-2)^2 - 1
y = 4 - 1
y = 3
The second point is (2,3). Answer 2
Note the y values are the same. You might expect that.
What is the third quartile of the following data set<br><br>
24,20,35,39,28,42,25,29,44,21,37
strojnjashka [21]
First, arrange the data:
20, 21, 24, 25, 28, 29, 35, 37, 39, 42, 44
You can use the formula 3/4 multiplied by the number of data + 1 to find the position of the 3rd quartile.
so it's going to be 3/4 x (11+1) = 9th position
the number in 9th position is 39 so that's the 3rd quartile
*written: seven million.
*expanded: 7,000,000+000,000
