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babymother [125]
3 years ago
10

In a West Texas school district the school year began on August 1 and lasted until May 31. On August 1 a Soft Drink company inst

alled soda machines in the school cafeteria. It found that after t months the machines generated income at a rate of f(t) = 300t/2t2 + 8 dollars per month. Find the total income, $Tscc, produced during the second semester beginning on January 1.
Mathematics
1 answer:
WINSTONCH [101]3 years ago
3 0

Answer:

$95.78

Step-by-step explanation:

f(t) = 300t / (2t² + 8)

t = 0 corresponds to the beginning of August.  t = 1 corresponds to the end of August.  t = 2 corresponds to the end of September.  So on and so forth.  So the second semester is from t = 5 to t = 10.

$T₂ = ∫₅¹⁰ 300t / (2t² + 8) dt

$T₂ = ∫₅¹⁰ 150t / (t² + 4) dt

$T₂ = 75 ∫₅¹⁰ 2t / (t² + 4) dt

$T₂ = 75 ln(t² + 4) |₅¹⁰

$T₂ = 75 ln(104) − 75 ln(29)

$T₂ ≈ 95.78

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Answer:

10/7 feet

Step-by-step explanation:

Let e = Ethan

k = Kayla

The following equations can de derived from the equation :

1/2 e = 2/3k

multiply both sides of the equation by 2

e = 4/3k --- 1

e + k = 10 --- 2

Substitute for e in equation 2

4/3k + k = 10

7/3k = 10

multiply both sides of the equation by 3/7

k = 30/7

Substitute for k in equation 1

e = (4/3) x 30/7 = 40/7

difference in length = 40/7 - 30/7 = 10/7

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y = 6x - 17 \\ y =  - 4x + 23 \\ then \\ 6 x - 17 =  - 4x + 23 \\ 10x = 40 \\ x = 4 \\ y = 7

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Looking for the answer to this
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<h2><u>Requi</u><u>red</u><u> Answer</u><u> </u><u>:</u><u>-</u></h2>

Given system of linear equations are ,

  • x + y = 2
  • -3x + y = 2

And we need to find the Solution of the linear equation . So let's Firstly number the equations .

\large{\red{\frak{ Given}}}\begin{cases} \sf x + y = 2\qquad ..........(i) \\\\\sf -3x + y = 2 \qquad ..........(ii) \\\end{cases}

<u>→</u><u> </u><u>Multipl</u><u>ying</u><u> </u><u>equⁿ</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>by</u><u> </u><u>3</u><u> </u><u>,</u>

=> 3 ( x + y ) = 2*3

=> 3x + 3y = 6

<u>→</u><u> </u><u>Addin</u><u>g</u><u> </u><u>the</u><u> </u><u>two</u><u> </u><u>equations </u><u>,</u><u> </u>

=> 3x + 3y -3y + y = 6 + 2

=> 4y = 8

=> y = 8/4

=> y = 2

<u>→</u><u> </u><u>Put</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>in</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>,</u>

=> x + y = 2

=> x + 2 = 2

=> x = 2- 2

=> x = 0

<h3><u>★</u><u> </u><u>Hence</u><u> the required solution is ( 0 , 2 ) .</u></h3>
7 0
2 years ago
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