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Sergio039 [100]
3 years ago
13

Write an equation of the line passing through ​(- 5​,4​) and having slope -7.

Mathematics
1 answer:
lubasha [3.4K]3 years ago
8 0

thre are 1286 so that how i get my answer



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A baker recorded the number of batches of
azamat

Answer:

B. The lower extreme increased.

Step-by-step explanation:

From the original box and whisker plot, the lower extreme (minimum) is 5 ; The upper extreme, maximum is 15.

The number of batches baked on the eight day is 20. This exceeds tbe previous maximum value. Hence, upper extreme( maximum) value of the new plot will change from 15 to 20.

The lower extreme isn't affected as the obtained value isn't below 5.

The median value will Increase and the upper quartile value will also increase. Once the upper quartile value increases, the interquartile range will also increase

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3 years ago
Which is the first step in simplifying the expression 2(x + 3) + 5?
mina [271]
I believe the answer would be B
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How many hectograms are in 45 centigrams?
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0.0045 hectograms are in 45 centigrams

Step-by-step explanation:

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3 years ago
3
Masteriza [31]

Answer:

<h3>Lucas and Zoe will both next visit their mother on 7th of May at the same time.</h3>

Step-by-step explanation:

<em>First</em><em>,</em><em> </em><em>find </em><em>the </em><em>first</em><em> </em><em>multiple </em><em>that </em><em>can </em><em>be </em><em>divisible </em><em>by </em><em>5</em><em> </em><em>and </em><em>8</em><em>:</em>

<em>4</em><em>0</em><em> </em><em>is </em><em>divisible </em><em>by </em><em>5 </em><em>and </em><em>8</em><em>.</em>

<em>Second</em><em>,</em><em> </em><em>find </em><em>the </em><em>days </em><em>in </em><em>April </em><em>and </em><em>subtract </em><em>7</em><em> </em><em>from </em><em>the </em><em>days:</em>

<em>April</em><em>=</em><em>3</em><em>0</em><em> </em><em>days</em><em>.</em>

<em>3</em><em>0</em><em>-</em><em>7</em><em>=</em><em> </em><em>2</em><em>3</em><em> </em><em>days</em><em>.</em>

<em>Finally,</em><em> </em><em>subtract </em><em>2</em><em>3</em><em> </em><em>from </em><em>4</em><em>0</em><em> </em><em>and </em><em>find </em><em>it </em><em>in </em><em>the </em><em>next </em><em>month</em><em>,</em><em> </em><em>which </em><em>is </em><em>May</em><em>:</em>

<em>4</em><em>0</em><em>-</em><em>2</em><em>3</em><em>=</em><em>1</em><em>7</em>

<em>Therefore</em><em>,</em><em> </em><em>they </em><em>will </em><em>both </em><em>next </em><em>visit </em><em>their </em><em>mother </em><em>on </em><em>the </em><em>7</em><em>t</em><em>h</em><em> </em><em>of </em><em>May.</em>

3 0
2 years ago
Log10(x^2+1)=1 <br> .......
sesenic [268]
2^{x} = 4 ----\ \textgreater \  x =  log_{2}4&#10;&#10; x^{2}  = 4 ----\ \textgreater \  x =  \sqrt{4}
5 0
3 years ago
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