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guapka [62]
3 years ago
13

Y varies directly as x and inversely as the square of z. y equals 10 when x equals 36 and z equals 6. Find y when x equals 2 and

z equals 4.
y​ =
nothing
Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0

Answer:

y = 20

Step-by-step explanation:

y =  \frac{kz}{x}  \\ 10 =  \frac{6k}{36}  \\ \frac{6k}{6}  = \frac{360}{6} \\ k= 60 \\  y =  \frac{4(60)}{2}  \\ y =  \frac{240}{2}  \\ y = 120

If this is right, then please make it the brainliest.

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M gets paid a set rate in his allowance for making his bed every morning. His rate is $0.50 earned for every morning that he mak
lord [1]

Answer:

Step-by-step explanation:

.50n=t

4 0
2 years ago
Read 2 more answers
You jog 6 and 2 thirds miles around a track each day. If you jogged that distance 4 times last week, how many miles did you jog?
Hunter-Best [27]
You jogged 26 2/3 miles because 6 2/3x4= 26 2/3
7 0
3 years ago
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The cost of a postage is determined by the following step function: How much would a package that weighs 3 ounces cost, in cents
bija089 [108]

Answer:

I think its C) 43. Let me know what you get

4 0
3 years ago
Josephine has a rectangular garden with an area of 2x2 + x – 6 square feet. A rectangle labeled 2 x squared + x minus 6 Which ex
GalinKa [24]

Answer:

2x^2 + x - 6 = rectangular garden: <u><em>length = 2x – 3 feet; width = x + 2 feet</em></u>

Step-by-step explanation:

(2x - 3)(x + 2) = 2x^2 + x - 6 =

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2x^2 + x - 6

You get the original equation from the two sides multiplied. :)

Hope this helps, have a good day.

7 0
2 years ago
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Find the approximate perimeter of ABC plotted below.
maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}

AB = \sqrt{4 + 4}

AB = \sqrt{16}

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}

BC = \sqrt{25 + 49}

BC = \sqrt{74}

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}

AC = \sqrt{47 + 25}

AC = \sqrt{74}

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0
3 years ago
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