The Reactance of a Capacitor is t<u>he resistance it has when alternating current (A/C) with a specific frequency (f) passes through it. </u>This is measured in ohms (Ω) and its formula is:
(1)
Where:
is the Reactance in ohms (Ω)
is the frequency of the alternating current in Hertz (
)
is the Capacitance of the Capacitor in Farad (
)
In this case we have a 25 mF capacitor with an applied frequency of 400 Hz.
Note ![1mF=1*10^{-3}F=0.001F](https://tex.z-dn.net/?f=1mF%3D1%2A10%5E%7B-3%7DF%3D0.001F)
Well, with the given data we have to solve (1):
Then:
XC=0.0159 Ω This is the Reactance of the Capacitor
If you would like to know what is quotient of 5/8 and 20, you can calculate this using the following steps:
the quotient of 5/8 and 20:
5/8 / 20 = 5/8 * 1/20 = 1/32
The correct result would be 1/32.
Solving the inequality
we get ![m>7](https://tex.z-dn.net/?f=m%3E7)
Step-by-step explanation:
We need to solve the inequality: ![-7m+4< -45](https://tex.z-dn.net/?f=-7m%2B4%3C%20-45)
Solving:
![-7m+4< -45](https://tex.z-dn.net/?f=-7m%2B4%3C%20-45)
Adding -4 on both sides:
![-7m+4-4< -45-4](https://tex.z-dn.net/?f=-7m%2B4-4%3C%20-45-4)
![-7m< -49](https://tex.z-dn.net/?f=-7m%3C%20-49)
Divide both sides by -7 and reverse the inequality:
![\frac{-7m}{-7}>\frac{-49}{-7}](https://tex.z-dn.net/?f=%5Cfrac%7B-7m%7D%7B-7%7D%3E%5Cfrac%7B-49%7D%7B-7%7D)
![m>7](https://tex.z-dn.net/?f=m%3E7)
So, solving the inequality
we get ![m>7](https://tex.z-dn.net/?f=m%3E7)
Keywords: Solving inequalities
Learn more about Solving inequalities at:
#learnwithBrainly
Answer:
the number of possibilities that can be drace himself up for the day is 216
Step-by-step explanation:
Given that
jun has 12 t-shirts,6 pairs of pants and 3 pairs of shoes
We need to find out the possibilities that can be drace himself up for the day
So here
![= 12C_1 \times 6C_1 \times 3C_1\\\\= \frac{12!}{1!(12 - 1)!} \times \frac{6!}{1!(6 - 1)!} \times \frac{3!}{1!(3 - 1)!}\\\\= \frac{12!}{1!(11)!} \times \frac{6!}{1!(5)!} \times \frac{3!}{1!(2)!}\\\\= 12 \times 6 \times 3\\\\= 216](https://tex.z-dn.net/?f=%3D%2012C_1%20%5Ctimes%20%206C_1%20%5Ctimes%20%203C_1%5C%5C%5C%5C%3D%20%5Cfrac%7B12%21%7D%7B1%21%2812%20-%201%29%21%7D%20%20%5Ctimes%20%5Cfrac%7B6%21%7D%7B1%21%286%20-%201%29%21%7D%20%5Ctimes%20%5Cfrac%7B3%21%7D%7B1%21%283%20-%201%29%21%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B12%21%7D%7B1%21%2811%29%21%7D%20%5Ctimes%20%20%5Cfrac%7B6%21%7D%7B1%21%285%29%21%7D%20%5Ctimes%20%20%5Cfrac%7B3%21%7D%7B1%21%282%29%21%7D%5C%5C%5C%5C%3D%2012%20%5Ctimes%206%20%5Ctimes%203%5C%5C%5C%5C%3D%20216)
Hence, the number of possibilities that can be drace himself up for the day is 216
The same would be considered and relevant too
Answer:
or ![32.312](https://tex.z-dn.net/?f=32.312)
Step-by-step explanation:
- Find a common denominator between the fractions, so it now looks like this: 300/1000 + 10/1000 + 2/1000 + 32
- 300/1000 + 10/1000 + 2/1000 + 32 = 32 + 312/1000
- 32 + 312/1000 = 32.312