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Svet_ta [14]
3 years ago
7

Frank Fitness found a correlation coefficient of —.74 between hours of strenuous exercise each week and a standard measure of bo

dy mass. He interprets this to mean that there is a: A weak, negative correlation between hours of strenuous exercise and body mass. B strong, positive correlation between hours of strenuous exercise and body mass. C weak, positive correlation between hours of strenuous exercise and body mass. D strong, negative correlation between hours of strenuous exercise and body mass.
Mathematics
1 answer:
irina1246 [14]3 years ago
5 0

A a B b C c D d E e F f G g H h I i J j K k L l M m N n O o P p Q q R r S s T t U u V v W w X x Y y Z z 1 2 3 4 5 6 7 8 9 0

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Solve the following
GREYUIT [131]
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4 0
2 years ago
Subtract.<br><br> 7 1/5 − (−3/5)
mojhsa [17]

This would just be 7 1/5 + 3/5 since the negative sign gets distributed and makes (-3/5) into a positive number.

From there you have basic math and you get 7 4/5.

5 0
3 years ago
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I need help with this math question due today
hammer [34]

Answer:

Please take a picture and ask it again, it had failed to access it.

3 0
3 years ago
Calcular los perimetros de las siguientes figuras porfa ayúdenme ya​
Basile [38]

Answer:

solo suma todos los valores x+4(3)+(x+x)

en el segundo x+5(2)+x+3(2)

en el tercero x-3+(2x+5)+(2x+5)

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7 0
3 years ago
The concentration of a drug in the bloodstream C(t) at any time t, in hours, is described by the equationC(t)=100t/t^2+25where t
alisha [4.7K]

Answer:

It will take 5 hours until it reaches its maximum concentration.

Step-by-step explanation:

The maximum concentration will happen in t hours. t is found when

C'(t) = 0

In this problem

C(t) = \frac{100t}{t^{2} + 25}

Applying the quotient derivative formula

C'(t) = \frac{(100t)'(t^{2} + 25) - (t^{2} + 25)'(100t)}{(t^{2} + 25)^{2}}

C'(t) = \frac{100t^{2} + 2500 - 200t^{2}}{(t^{2} + 25)^{2}}

C'(t) = \frac{-100t^{2} + 2500}{(t^{2} + 25)^{2}}

A fraction is equal to zero when the numerator is 0. So

-100t^{2} + 2500 = 0

100t^{2} = 2500

t^{2} = 25

t = \pm \sqrt{25}

t = \pm 5

We use only positive value.

It will take 5 hours until it reaches its maximum concentration.

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3 years ago
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