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Ostrovityanka [42]
3 years ago
10

In two to three paragraphs, come up with a way that you could incorporate the most technologically advanced gaming into your onl

ine education.
Needs to be completely original... NO Plagarism. Answer can't have been used in another problem or on any other site. My School will know.

Need by 4/03/2019
Computers and Technology
1 answer:
Marina CMI [18]3 years ago
7 0

nobody cares about plagiarism dude

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Sharon is a network engineer for your firm and is investigating the WAN connection into the hot site. In the event of operations
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Answer:

The correct answer to the following question will be "Peak capacity" and "Bandwidth starvation".

Explanation:

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⇒ Rs =1 (Figure 1 and Equation 1)

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3 years ago
Write the following function without using the C++ string class or any functions in the standard library, including strlen(). Yo
dolphi86 [110]

Answer:

The function in C++ is as follows

int chkInd(string str1, string str2){    

int lenstr1=0;

while(str1[lenstr1] != '\0'){  lenstr1++;  }

int index = 0; int retIndex=0;

for(int i=lenstr1-1;i>=0; i--){

   while (str2[index] != '\0'){

       if (str1[i] == str2[index]){

           retIndex=1;

           break;         }

       else{   retIndex=0;      }

  index++;    }

  if (retIndex == 0){   return i;   }else{return -1;}}

}

Explanation:

This defines the function

int chkInd(string str1, string str2){    

First, the length of str1 is initialized to 0

int lenstr1=0;

The following loop then calculates the length of str1

while(str1[lenstr1] != '\0'){  lenstr1++;  }

This initializes the current index and the returned index to 0

int index = 0; int retIndex=0;

This iterates through str1

for(int i=lenstr1-1;i>=0; i--){

This loop is repeated while there are characters in str2

   while (str2[index] != '\0'){

If current element of str2 and str1 are the same

       if (str1[i] == str2[index]){

Set the returned index to 1

           retIndex=1;

Then exit the loop

           break;         }

If otherwise, set the returned index to 0

       else{   retIndex=0;      }

Increase index by 1

  index++;    }

This returns the calculated returned index; if no matching is found, it returns -1

  if (retIndex == 0){   return i;   }else{return -1;}}

}

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