Answer:
A is the answer: Mobile marketing, Social media marketing and direct mail marketing
Explanation:
Option A is most likely correct because it is an intersection of both direct and digital marketing.
Option B is not the answer as direct response television marketing is listed
Option C is not the answer because online marketing and social media marketing belong to digital marketing while telemarketing belong the direct marketing
Option D is also not the answer as it just list the general category of marketing tools
Option E look like a good option but among the listed forms Social media marketing belong to digital marketing while telemarketing and kiosk marketing belong to digital marketing.
You know u can find answer on google
Answer:
See Explanation
Explanation:
The question is incomplete as there is no link pointing to the houseType struct of chapter 1.
So, I've answered the question from scratch
See attachment for explanation where I used comments to explain each line.
The program is as follows:
#include <iostream>
using namespace std;
struct houseType{
int firstHouse, secondHouse;
};
int main()
{
houseType hT;
cout << "Enter the price of both house: ";
cin>> hT.firstHouse;
cin>> hT.secondHouse;
if(hT.firstHouse == hT.secondHouse){ cout<<"true"; }
else{ cout<<"false"; }
return 0;
}
Answer:
False.
Explanation:
A stethoscope is a medical instrument which is used for listening to the work of the heart and lungs. It consists of a microphone that rests on the patient's chest, and rubber tubes that bring the sound to the earphones. An ordinary stethoscope does not have any moving or electrical parts, as it only mechanically conducts sound from the patient's chest to the doctor's ear. One of the simplest examinations that doctors perform today is listening to the lungs and heart with a stethoscope. With the help of this instrument, noises are heard during the work of the lungs and heart.
Answer: provided in the explanation segment
Explanation:
taking a step by step process for this, we will analyze this problem,
we have that the Word size = 8 bytes
Cache size = 128 KB = 128×2¹⁰ bytes = 2¹⁷ bytes
(a). we are asked to cal for fully associative mapping with line size of 4 words.
- fully associative mapping with line size of 4 words = 4 × 8 = 32 bytes
- offset = log₂³² = 5 bit
- tag = 32 - (5+0) = 27 bit
- index bit = 0
(b). Direct mapping with the line size of 8 words:
- here the line size = 8×8 = 64 bytes
- no of lines = 2¹⁷/2⁶ = 2¹¹ lines
- offset = log ₂(2⁶) = 6 bit
- index = log ₂(2¹¹) = 11 bit
- tag = 32 - (5 +11) = 15 bit
(c). 2-way set associated mapping with the line size of 1 word:
- no of lines = 2¹⁷/2³ = 2¹⁴ lines
- offset = log₂(2³) = 3 bit
- no of sets = 2¹⁴/2 = 2¹³ sets
- index = log₂(2¹³) = 13 bit
- tag = 32 - (3+13) = 16 bit
(d). 8-way set associated mapping with the line size of 2 words:
8-way set associated mapping with the line size of 2 = 2*8 = 16 bytes
- no of lines = 2¹⁷/2⁴ = 2¹³ lines
- no of sets = 2¹³/2³ = 2¹⁰ sets
- offset = log₂¹⁶ = 4 bit
- index = log ₂(2¹⁰) = 10 bit
- tag = 32 - (4+10) = 18 bit
cheers i hope this helps!!!!