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wolverine [178]
3 years ago
13

To exclude members of a group from the basic permissions for a folder, which type of permission would you assign? Deny Allow Mod

ify Read & Execute
Computers and Technology
1 answer:
oksano4ka [1.4K]3 years ago
4 0

Answer:

Deny

Explanation:

Under the New Technology System, the Deny permission is applied when the administrator wants to overrule the permission given to members of a group. The Allow and Deny options help in regulating access to the components of the system. Only authorized groups are granted access to the files.

Most times, the Deny permission is considered before the Allow permission. If the user is denied access to some files and granted access to some, the deny permission is most times considered first.

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Common icons found on the Windows desktop are _____.
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Answers- My computer, My Documents and Recyle bin.

2,3,4 option

5 0
3 years ago
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Print "Censored" if userInput contains the word "darn", else print userInput. End with newline. Ex: If userInput is "That darn c
barxatty [35]

Answer:

#include <string>

#include <iostream>

using namespace std;

int main() {

string userInput;

getline(cin, userInput);

// Here, an integer variable is declared to find that the user entered string consist of word darn or not

int isPresent = userInput.find("darn");

if (isPresent > 0){

cout << "Censored" << endl;

// Solution starts here

else

{

cout << userInput << endl;

}

// End of solution

return 0;

}

// End of Program

The proposed solution added an else statement to the code

This will enable the program to print the userInput if userInput doesn't contain the word darn

6 0
3 years ago
in java how do i Write a method named isEven that accepts an int argument. The method should return true if the argument is even
Veseljchak [2.6K]
<h2>Answer:</h2><h2>============================================</h2>

//Class header definition

public class TestEven {

   

   //Method main to test the method isEven

   public static void main(String args[ ] ) {

       

       //Test the method isEven using numbers 5 and 6 as arguments

       System.out.println(isEven(5));

       System.out.println(isEven(6));

     

   }

   

   //Method isEven

   //Method has a return type of boolean since it returns true or false.

   //Method has an int parameter

   public static boolean isEven(int number){

       //A number is even if its modulus with 2 gives zero

      if (number % 2 == 0){

           return true;

       }

       

       //Otherwise, the number is odd

       return false;

   }

}

====================================================

<h2>Sample Output:</h2>

=========================================================

false

true

==========================================================

<h2>Explanation:</h2>

The above code has been written in Java. It contains comments explaining every part of the code. Please go through the comments in the code.

A sample output has also been provided. You can save the code as TestEven.java and run it on your machine.

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