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2 years ago

Write a numerical expression that matches the phrase: 8 more than the product of 3 and 2.

Mathematics

1 answer:

eduard2 years ago

4 0

Answer:

8+3(2)

Step-by-step explanation:

8 more than indicates addition, so that makes the first part of the expression 8+.

The product of 3 and 2 indicates multiplication, since product means the result of multiplication. That finishes the expression with 3(2).

In conclusion, a numerical expression that matches the states phrase is 8+3(2). You can also do 8+3×2 too, as they equal the same thing.

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ILL MARK BRAINLIEST AND 20 POINTS FOR THE FIRST TO HELP! ITS DUE IN 10! PLEASE AND THANKS

Ugo [173]

Answer:

7/30

Step-by-step explanation:

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2 years ago

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Help pls! simplify -6 x^{2} ÷ 12 - 2(-7) a. -17 b. 35 c. -35 d. 11

Mariana [72]

Answer:

Step-by-step explanation:

Given: $\frac{-6^{2}}{12} -2(-7)$

Using PEDMAS rule to solve it.

Now, simplifying:

We first open parenthesis which is (-7) = -7

= $\frac{-6^2}{12}-2\times -7$

Now, we evaluate the exponent which is $-6^2=-36$

Next, we divide -36 by 12 to get -3

= $\frac{-36}{12}-2\times -7 \\= -3 -2\times -7$

Next, we multiply -2 and -7 to get 14

= $-3 + 14$

Lastly, we add -3 and 14 to get 11

= $11$

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3 years ago

Eight less than the product of 7 and a number is 3. Use the variable w for the unknown number

Tpy6a [65]

W = unknown number
7w - 8 = 3 (product of 7 and a number, w, subtract 8) is 3
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w = 11/7

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3 years ago

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A rectangle has its vertices at (-4, -3), (-4,7), (1,7), (1, -3). What part, in percent, of the rectangle is located in Quadrant

Rasek [7]

Consider the attached figure. The whole rectangle is ABCD, while AEGF is the part located in the third quadrant. In fact, this quadrant is composed by all the points with both coordinates negative.

To answer the question, let's compute the area of the two rectangles and see what part of ABCD is AEGF.

A and B have the same x coordinate, so the length of AB is given by the absolute difference of their y coordinates:

$\overline{AB} = |A_y-B_y| = |-3-7| = |-10| = 10$

Similarly, but exchanging the role of x and y, we compute the length of BC:

$\overline{BC} = |B_x-C_x| = |-4-1| = |-5| = 5$

So, the area of the rectangle is $\overline{AB} \cdot \overline{BC} = 10\cdot 5 = 50$

The same procedure allows us to compute width and height of the sub-rectangle in the third quadrant:

$\overline{AE} = |A_y-E_y| = |-3-0| = |-3| = 3$

$\overline{EG} = |E_x-G_x| = |-4-0| = |-4| = 4$

So, the area of the portion located in the third quadrant is $\overline{AE} \cdot \overline{EG} = 3\cdot 4 = 12$

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$\cfrac{\text{area }AEGF}{\text{area }ABCD} = \cfrac{12}{50}$

If we want this ratio to be a percentage, just make sure that the denominator is 100:

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2 years ago

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Annette [7]

Brian (I think you meant Brian haha..) is incorrect because the tenth place is the number right after the decimal which is a 4. If you are rounding to the tenth place that means that you have to look at the number to the right of that, which is 4. 5 and up means you round up and 4 and down means you round down. This is a 4, so you keep the 4 after the decimal and get rid of the last 4. Therefore, when rounded it would be: 4.4.
Hope this helped! Good luck! :)

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