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marishachu [46]
3 years ago
11

How many distinguishable 5-letter combinations are possible of the letters of the word TIGHT?

Mathematics
2 answers:
Cloud [144]3 years ago
7 0
The answer is B hope this helps
Anton [14]3 years ago
6 0

Answer:

A. 40 combinations

we have 8 x 5 = 40

Step-by-step explanation:

Would be 60 as 3 letter words with 5 letters.

The logic is that all letters are being used to their maximum and with numbers 3 within 5 or 5 within 5 the maximum that cna be used is 12 rotation for 3 per letter or 8 rotaion for 5. Then we have 5 rotations = 60 for 3 and 40 for 5.   Another logic is the many combinations can you make from the numbers 1 2 3 4 5 not multiplying?

The rearrangement of 5 figure numbers will be 5x4x3x2x1 which is 120 combinations, when you don't repeat a number.

We see that 4+3 +2+1 = 10 and shows less than 5 number  combinations at 120, and then we have 5

5:10 ratio = 5/15 = 1/3

This = 1/3 of 120 =40

Then we find answer is 40 as compact 5 letter words from the word tight.

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The unit numbers can be 2,4,6.Suppose 2 as the unit number we can form 20 numbers the same way for 4 and 6 so totally 60 numbers.
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4.
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True or False: Point estimation is a form of statistical inference in which, based on the sample data, we estimate the unknown p
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Answer:

True

Step-by-step explanation:

Point estimation of a population parameter provides an estimate of  a single value calculated from the sample that is likely to be close to its value to the unknown parameter. Itis to be noted that a point estimate will not in general be equal to the population parameter as the random sample used is one of the many possible samples which could be chosen from the population.

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6 0
3 years ago
Sam scored 43, 48, and 42 points on three tests. How many points should he get on the fourth test to get an average score of 50?
tatiyna

So we know that an average is the sum of the scores divided by the number of scores that were added together. In this case we are going to be dealing with 4 tests. So let's say x is the score for our fourth test. We can create this equation:

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So then we need to simplify the top:

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Then multiply by 4 on both sides to get rid of the denominator:

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Then solve for x:

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So now we know that Sam needs to score a 67 on the fourth test to have an average score of 50.

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