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V125BC [204]
2 years ago
11

A student has a total of 233 points on three tests. The scores on the first and second tests are the same. The third score excee

ds the second (or the first) by 14. Find the three scores.
Mathematics
1 answer:
skad [1K]2 years ago
5 0

Answer:

Let the scores on the first two test be x

Let score for third test be 14 exceeds second( or first) = x + 14

Total = 233

x + x + (x + 14) = 233

3x + 14 = 233

3x = 219

x = 73

Score of the third test = x + 14 = 73 + 14 = 87

Therefore, the scores are 73, 73, 87

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Answer:

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Step-by-step explanation:

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First, recall that the equation of a circle is given by:

(x-h)^2+(y-k)^2=r^2

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.

Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:

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Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:

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Simplify. Thus:

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(x-7)^2+(y-2)^2=34

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