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e-lub [12.9K]
3 years ago
15

4 fewer airports than Missouri

Mathematics
1 answer:
Vesnalui [34]3 years ago
8 0
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Can somebody help me with this math problem?
Travka [436]

Answer:

integer and rational

Step-by-step explanation:

hfjbawenjrcuwit3wrjm3iowrmkfw3klarmfwesdjkncfkelrnmfKWCNRQJWKSRNCJKWrnq

4 0
3 years ago
How do you calculate the area and the perimeter of a parallelogram and a triangle?
Mnenie [13.5K]

for parallelograms:

area = b(h)

so basically, the length times the height. just like how you would find the area of a square.

perimeter: just add all of the sides together.

for triangles:

area = 1/2(b) x h

so half the length multiplied by the height. for example, if the length was 4, you have to use half of that. so that means 2 times whatever the height is.

perimeter: again, just add all three sides together

7 0
3 years ago
Read 2 more answers
Marshall began making a grilled cheese sandwich at 6:13 P.M. The sandwich was ready at 6:24 P.M. How long did it take Marshall t
jasenka [17]
It took him 11 minutes.
3 0
3 years ago
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<img src="https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7BQuestion%3A%7D" id="TexFormula1" title="\huge\boxed{Question:}" alt="\huge\b
iragen [17]

The equivalent expression for (x + 4)^5 is x^5+ 20x^4+ 160x^3 + 640x^2 + 1280x  + 1024

The expression is given as:

(x + 4)^5

To expand the expression, we make use of Pascal triangle, where:

5:= 1 5 10 10 5 1

So, we have:

(x + 4)^5 = 1 * x^5 * 4^0 + 5 * x^4 * 4^1  + 10 * x^3 * 4^2 + 10 * x^2 * 4^3 + 5 * x * 4^4 + 1 * x^0 * 4^5

Evaluate the exponents

(x + 4)^5 = 1 * x^5 * 1 + 5 * x^4 * 4 + 10 * x^3 * 16 + 10 * x^2 * 64 + 5 * x * 256 + 1 *1 * 1024

Evaluate the products

(x + 4)^5 = x^5+ 20x^4+ 160x^3 + 640x^2 + 1280x  + 1024

Hence, the equivalent expression for (x + 4)^5 is x^5+ 20x^4+ 160x^3 + 640x^2 + 1280x  + 1024

Read more about binomial expressions at:

brainly.com/question/13602562

7 0
2 years ago
Read 2 more answers
Using the rotation R, can you create a function R(ABCD) that is equivalent to the reflection of ABCD across both the x-axis and
galben [10]

The reflection over the x-axis is given by:

R(x,y)\to(-x,y)

And the reflection over the y-axis is given by:

R(x,y)\to(x,-y)

Thus, a function that is equivalent to the reflection of ABCD across both axis would be:

R(x,y)\to(-x,-y)

6 0
1 year ago
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