4 fewer airports than Missouri

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$

In which

$(A \cup B) = a + b + (A \cap B)$

65% were found to be proficient in both reading and mathematics.

This means that $A \cap B = 0.65$

78% were found to be proficient in mathematics

This means that $B = 0.78$

$B = b + (A \cap B)$

$0.78 = b + 0.65$

$b = 0.13$

85% of the students were found to be proficient in reading

This means that $A = 0.85$

$A = a + (A \cap B)$

$0.85 = a + 0.65$

$a = 0.20$

Proficient in at least one:

$(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98$

What is the probability that the student is proficient in neither reading nor mathematics?

$(A \cup B) + C = 1$

$C = 1 - (A \cup B) = 1 - 0.98 = 0.02$

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0

2 years ago

WILL MARK BRAINLIEST An architect is drafting a scale drawing of a house for an upcoming project. The customer wants the front o

kobusy [5.1K]

Answer:

60 ft is 720 in. I did 720/15...that equals 48. At this point i think each in in the drawing is a foot, so every one in is 48 ft.

(x+48)

there is no y because they only give information about one side. hope this helps. :)

Step-by-step explanation:

4 0

2 years ago

84 is 30% of what number? 2.8 25.2 280 2520

frez [133]

The right answer is 280

please see the attached picture for full solution

Hope it helps

Good luck on your assignment

4 0

2 years ago

Read 2 more answers

Given the Venn diagram below, if a student is randomly selected, what is the probability that he or she is attending both colleg

guajiro [1.7K]

Add up all the values shown:
64+28+52+56 = 200

This result indicates that there are 200 students total.

Of these 200 total people, there are 28 who are attending both colleges. This is the value shown in the overlapping region of the two circles.

Divide the two values (28 and 200) to get...
28/200 = 0.14 = 14%

The probability as a decimal value is 0.14 which is saying there's a 14% chance of picking someone who goes to both colleges.

3 0

3 years ago

Read 2 more answers

3^sqrt -64w^12 <img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20-%2064w%5E%7B12%7D%7D%20" id="TexFormula1" title=" \s

Agata [3.3K]

-64=(-4)³, w^12=(w^4)³
the result is -4w^4

7 0

2 years ago