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Ira Lisetskai [31]
3 years ago
7

How to solve y for this problem

Mathematics
1 answer:
ser-zykov [4K]3 years ago
7 0
You do \frac{sin(y)}{2} = \frac{sin30}{what you got for x} and then cross multiply and simply it.

(what you got for x)sin(y)=2sin30
divide (what you got for x) to both side
you should get something like sin(y)= \frac{2sin30}{what you got for x}
then just use a calculator and do sin^{-1} ( \frac{2sin30}{what you got for x} )
You might be interested in
given y>0 and dy/dx=(3x^2+4x)/yif the point (1,√10) is on the graph relating x and y, then what is y when x=0
jonny [76]
\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{3x^2+4x}y\iff y\,\mathrm dy=(3x^2+4x)\,\mathrm dx
\implies\displaystyle\int y\,\mathrm dy=\int(3x^2+4x)\,\mathrm dx
\implies \dfrac12y^2=x^3+2x^2+C

When x=1 you have y=\sqrt{10}, so

\dfrac12(\sqrt{10})^2=1^3+2(1)^2+C\implies 5=1+2+C\implies C=2

and so the particular solution to the ODE is

\dfrac12y^2=x^3+2x^2+2

Then when x=0, you get

\dfrac12y^2=0^3+2(0)^2+2=2
\implies y^2=4
\implies y=2

where we omitted the negative root because it's given that y>0.
4 0
3 years ago
Please explain whether it's true or false? Thanks
svlad2 [7]
15. true 16. false in my coculations.
7 0
3 years ago
What is the ratio of the intensities of an earthquake PP wave passing through the Earth and detected at two points 19 kmkm and 4
Tamiku [17]

Answer:

The ratio of the intensities is roughly 6:1.  

Step-by-step explanation:

The intensity I() of an earthquake wave is given by:

I = \frac{P}{4\pi d^{2}}

<em>where P: is the power ans d: is the distance. </em>

Hence, the ratio of the intensities of an earthquake wave passing through the Earth and detected at two points 19 km and 46 km from the source is:

\frac{I_{1}}{I_{2}} = \frac{P/4\pi d_{1}^{2}}{P/4\pi d_{2}^{2}}

<em>where I₁ = P/4πd₁², d₁=19 km, I₁ = P/4πd₂² and d₂=46 km     </em>

\frac{I_{1}}{I_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}

\frac{I_{1}}{I_{2}} = \frac{46 km^{2}}{19 km^{2}}

\frac{I_{1}}{I_{2}} = 5.9:1

Therefore, the ratio of the intensities is roughly 6:1.  

 

I hope it helps you!    

3 0
3 years ago
Distribute and simplify the radicals below (√12+6)(-√8-√2)
Hatshy [7]

For this case we have the following expression:

(\sqrt {12} +6) (- \sqrt {8} - \sqrt {2})

We apply distributive property:

(\sqrt {12} * - \sqrt {8}) + (\sqrt {12} * - \sqrt {2}) + (6 * - \sqrt {8}) + (6 * - \sqrt {2} ) =\\- \sqrt {96} - \sqrt {24} -6 \sqrt {8} -6 \sqrt {2} =

We rewrite in equivalent form:

- \sqrt {4 ^ 2 * 6} - \sqrt {2 ^ 2 * 6} -6 \sqrt {2 ^ 2 * 2} -6 \sqrt {2} =\\-4 \sqrt {6} -2 \sqrt {6} -6 * 2 \sqrt {2} -6 \sqrt {2} =

-4 \sqrt {6} -2 \sqrt {6} -12 \sqrt {2} -6 \sqrt {2} =\\-6 \sqrt {6} -18 \sqrt {2}

Answer:

-6 \sqrt {6} -18 \sqrt {2}

8 0
3 years ago
Read 2 more answers
Please answer A and B and give an explanation and show work. thank you!
NNADVOKAT [17]
Dont know a but b is 
75=100-2p
75 minus 100 = -25=-2p
-25/-2= p 
p=$12.50
4 0
3 years ago
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