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Ira Lisetskai [31]
3 years ago
7

How to solve y for this problem

Mathematics
1 answer:
ser-zykov [4K]3 years ago
7 0
You do \frac{sin(y)}{2} = \frac{sin30}{what you got for x} and then cross multiply and simply it.

(what you got for x)sin(y)=2sin30
divide (what you got for x) to both side
you should get something like sin(y)= \frac{2sin30}{what you got for x}
then just use a calculator and do sin^{-1} ( \frac{2sin30}{what you got for x} )
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Answer:

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  • 10(x +1)^2
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Step-by-step explanation:

When your desired form is expanded, it becomes ...

  a(x +b)^2 = a(x^2 +2bx +b^2) = ax^2 +2abx +ab^2

This tells you the overall factor (a) is the leading coefficient of the given trinomial. Factoring that out, you can find b as the root of the remaining constant.

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c) 1/4x^2 +x +1 = 1/4(x^2 +4x +4) = 1/4(x +2)^2

d) 3x^2 +5x +25/12 = 3(x^2 +5/3x +25/36) = 3(x +5/6)^2

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<em>Additional comment</em>

If you know beforehand that the expressions can be factored this way, finding the two constants (a, b) is an almost trivial exercise. It gets trickier when you're trying to write a general expression in vertex form (this form with an added constant). For that, you must develop the value of b from the coefficient of the linear term inside parentheses.

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