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2 years ago

The graph of g(x), shown below, is a vertical shift of the graph of f(x) = 2x.

Mathematics

2 answers:

Nikitich [7]2 years ago

7 0

Answer:

G(x)=2x-1

Step-by-step explanation:

never [62]2 years ago

4 0

Answer:

C or D

Step-by-step explanation:

Given y = f(x) then

y = f(x) + c represents a vertical translation

• If c > 0 then a vertical shift up of c units

• If c < 0 then a vertical shift down of c units

Hence

g(x) = 2x - 1 or g(x) = 2x + 1 ( depending on the value of c )

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Write an algebraic rule to describe the translation C'(5, -4) -> C'(-2, 1)

katrin2010 [14]

The answer is c. To get to (-2,1) from (5,-4), you have to add subtract 7 from 5 and add 5 to 1.

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2 years ago

Can someone help me

Sphinxa [80]

I think it’s 6 units

5 0

2 years ago

if i supposedly got 2 cats and trained them to bring me quarters and they did and supposedly everyday i got 10 quarters how much

ivanzaharov [21]

Answer:

After a year you would have $1,825

Step-by-step explanation:

Amount for one cat a day in cents

10x25=250

Amount for one cat for a year in cents

250x365=91,250

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8 0

1 year ago

Find the perimeter of the pentagon MNPQR with vertices M(2, 4), N(5, 8), P(8, 4), Q(8, 1), and R(2, 1)

Gekata [30.6K]

Answer:

The pentagon MNPQR has a perimeter of 22 units.

Step-by-step explanation:

Geometrically speaking, the perimeter of the pentagon is the sum of the lengths of each side, that is:

$p = MN + NP + PQ + QR + RM$ (1)

$p = \sqrt{\overrightarrow{MN}\,\bullet \, \overrightarrow{MN}} + \sqrt{\overrightarrow{NP}\,\bullet \, \overrightarrow{NP}} + \sqrt{\overrightarrow{PQ}\,\bullet \, \overrightarrow{PQ}} + \sqrt{\overrightarrow{QR}\,\bullet \, \overrightarrow{QR}} + \sqrt{\overrightarrow{RM}\,\bullet \, \overrightarrow{RM}}$ (1b)

If we know that $M(x,y) = (2,4)$ , $N(x,y) = (5,8)$ , $P(x,y) = (8,4)$ , $Q(x,y) = (8,1)$ and $R(x,y) = (2,1)$ , then the perimeter of the pentagon MNPQR is:

$p =\sqrt{(5-2)^{2}+(8-4)^{2}} + \sqrt{(8-5)^{2}+(4-8)^{2}}+\sqrt{(8-8)^{2}+(1-4)^{2}}+\sqrt{(2-8)^{2}+(1-1)^{2}}+\sqrt{(2-2)^{2}+(4-1)^{2}}$ $p = \sqrt{3^{2}+4^{2}} + \sqrt{3^{2}+(-4)^{2}}+\sqrt{0^{2}+(-3)^{2}}+\sqrt{(-6)^{2}+0^{2}}+\sqrt{0^{2}+3^{2}}$