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gladu [14]
3 years ago
10

Help needed with all pls

Mathematics
1 answer:
Olenka [21]3 years ago
3 0
#5 is 5 days
40×5=200
200+150=250

20×5=100
100+150=250
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During a sale a dress decreased in price from $60 to $48 what was the percent of decrease
Elza [17]

Answer:

The percent decrease was 20%

Step-by-step explanation:

In order to find this, use the percent change equation.

(New - Old)/(Old) * 100 = % Change

Now input 48 for the New price and 60 for the Old price.

(48 - 60)/(60) * 100 = % Change

12/60 * 100 = % Change

.2 * 100 = % Change

20 = % Change

3 0
3 years ago
Let A = {x : 2x² + 3x - 2 = 0} and B = {x : x² + 3x - 4 = 0 } find (A U B) × (A Π B)​
ivann1987 [24]

Given :

  • A = {x: 2x² + 3x - 2 = 0 }
  • B = {x : x² + 3x - 4 = 0 }

To find :

  • (A U B ) × (A Π B )

Solution :-

<u>The </u><u>first </u><u>set </u><u>is </u><u>,</u>

  • A ={x : 2x² + 3x - 2 = 0}

<u>Solving</u><u> </u><u>the </u><u>Quadratic</u><u> equation</u><u> </u><u>,</u>

  • 2x² + 3x - 2 = 0
  • 2x² + 4x - x - 2 = 0
  • 2x( x + 2) -1( x + 2 ) = 0
  • (2x -1) ( x + 2) = 0
  • x = 0.5 , -2

<u>Hence</u><u> </u><u>,</u>

  • A ={0.5, -2}

<u>The </u><u>second</u><u> </u><u>set </u><u>is </u><u>,</u>

  • B ={ x :x² + 3x - 4 = 0 }

<u>Solving</u><u> the</u><u> Quadratic</u><u> equation</u><u> </u><u>,</u>

  • x² + 3x - 4 = 0
  • x² + 4x - x - 4 = 0
  • x( x + 4)-1 ( x +4) = 0
  • (x + 4) ( x -1) = 0
  • x = 1 , -4

<u>Hence</u><u> </u><u>,</u>

  • B ={1,4}

<u>Now </u><u>,</u>

  • A U B = { 0.5 , 1 , 4 , -2}
  • A Π B = {∅ }

Since AΠ B is a null set , hence ,

  • A × B = {∅}
8 0
3 years ago
Select correct answer
Sergio [31]

Answer:

The values of p in the equation are 0 and 6

Step-by-step explanation:

First, you have to make the denominators the same. to do that, first factor 2p^2-7p-4 = \left(2p+1\right)\left(p-4\right)2p

2

−7p−4=(2p+1)(p−4)

So then the equation looks like:

\frac{p}{2p+1}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{5}{p-4}

2p+1

p

−

(2p+1)(p−4)

2p

2

+5

=−

p−4

5

To make the denominators equal, multiply 2p+1 with p-4 and p-4 with 2p+1:

\frac{p^2-4p}{(2p+1)(p-4)}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{10p+5}{(p-4)(2p+1)}

(2p+1)(p−4)

p

2

−4p

−

(2p+1)(p−4)

2p

2

+5

=−

(p−4)(2p+1)

10p+5

Since, this has an equal sign we 'get rid of' or 'forget' the denominator and only solve the numerator.

(p^2-4p)-(2p^2+5)=-(10p+5)(p

2

−4p)−(2p

2

+5)=−(10p+5)

Now, solve like a normal equation. Solve (p^2-4p)-(2p^2+5)(p

2

−4p)−(2p

2

+5) first:

(p^2-4p)-(2p^2+5)=-p^2-4p-5(p

2

−4p)−(2p

2

+5)=−p

2

−4p−5

-p^2-4p-5=-10p+5−p

2

−4p−5=−10p+5

Combine like terms:

-p^2-4p+0=-10p−p

2

−4p+0=−10p

-p^2+6p=0−p

2

+6p=0

Factor:

p=0, p=6p

7 0
3 years ago
Read 2 more answers
Please give me the correct answer ​
ArbitrLikvidat [17]

Answer:

11

Step-by-step explanation:

Just count it

6 0
3 years ago
Read 2 more answers
3) INITII equation y=-x+ 4<br> equation<br> W10<br> slope (m) = _<br> y-intercept =
vodomira [7]

Answer:

slope (m) = 1 and intercept = -4

Step-by-step explanation:

comparing with Y = mX - c

4 0
3 years ago
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