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Oksanka [162]
3 years ago
12

HELP PLEASEEEEEEE ASP!!

Mathematics
2 answers:
Monica [59]3 years ago
7 0

Answer:

Step-by-step explanation:

Slope formula= rise over run, or y2-y1 over x2-x1

y2=-4 y1=-18 x2=-7 x1=-7

-4-(-18)/-7-(7)

-22/-14 negative

Ludmilka [50]3 years ago
3 0

Answer:

7/11

Step-by-step explanation:

the slope is positive. tell me what happens

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Helppppppp please, all math lovers I'm calling for you​
Katen [24]

Answer:

Dive by n square root two, also option one.

Step-by-step explanation:

The first step to any algebra equation is to isolate the variable and you do that by divide square root 2 since it cancels out on the left side and now n is alone.

Hoped that helped :)

8 0
2 years ago
Lim (sin(pi/x)) as x tends to 0 from both sides​
strojnjashka [21]

Hello from MrBillDoesMath!

Answer:

Limit does not exist.

Discussion:

The function 1/x has a vertical asymptote as x approaches 0 so

sin (pi/x) has no limit as x approaches 0. In fact, it oscillates wildly between -1 and 1 as x approaches 0. See attached graph of function

Thank you,

MrB

8 0
3 years ago
6 to the second power ÷ [(4.3×3)+5.1]
Black_prince [1.1K]
2 is the answer
That’s the answer.
8 0
3 years ago
While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
3 years ago
Need help seriously
Dima020 [189]
It’s not hard bro you gotta lean probability it’s really easy
5 0
3 years ago
Read 2 more answers
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