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Oksanka [162]
3 years ago
12

HELP PLEASEEEEEEE ASP!!

Mathematics
2 answers:
Monica [59]3 years ago
7 0

Answer:

Step-by-step explanation:

Slope formula= rise over run, or y2-y1 over x2-x1

y2=-4 y1=-18 x2=-7 x1=-7

-4-(-18)/-7-(7)

-22/-14 negative

Ludmilka [50]3 years ago
3 0

Answer:

7/11

Step-by-step explanation:

the slope is positive. tell me what happens

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Which answer choice best represents 3/15?
uysha [10]

Uhh... what are the options?

Here's some possible ones:

0.2

1/5

4 0
2 years ago
Read 2 more answers
Hi, Please i need help with this question. Workings would be deeply appreciated .
kupik [55]

Answer:

k = ⅕  

Step-by-step explanation:

The slope-intercept equation for a straight line is

y = mx + b, where

m = the slope and

b = the y-intercept

Data:

(3,4)     = a point on the line

(3k,0)   = x-intercept

(0,-5k) = y-intercept

Calculations:

1. Slope

m = (y₂ - y₁)/(x₂ - x₁) = (-5k - 0)/(0 - 3k) = -5/(-3) = ⁵/₃

This makes the equation

y = ⁵/₃x - 5k

2. k

Insert the value of the known point: (3,4)

4 = (⁵/₃)(3) - 5k

4 = 5 - 5k

-1 = -5k

k = ⅕

The figure below shows your graph passing through (3,4) with intercepts 3k and -5k on the x- and y-axes respectively .

 

8 0
3 years ago
Pls help me ! i need help
Blizzard [7]

Answer:

what do you need help with?

7 0
3 years ago
Read 2 more answers
ILL MARK BRAINIEST IF YOU CAN DO THIS RIGHT!!!
Bumek [7]

Answer:  Slope: -1/2  

Step-by-step explanation:  To find slope take 2 points that lie on the line and use this formula to solve:  <em> </em>I will use (0, -2) and (2, -3) to solve

                                                                       ↑    ↑           ↑   ↑

y2 - y1                                                             x1  y1          x2  y2

-----------

x2 - x1

So, for this question, substitute the x and y values from the points above to solve.

-3 - (-2)      

----------- =  - 1/2

2 - 0

Hope this helped. :)

 

5 0
2 years ago
PLease help me ASAP PLZ
garik1379 [7]

Question- The image is appearing blank for me, could you try and re-send it or forward it to me. Thank you.

8 0
2 years ago
Read 2 more answers
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