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3 years ago

Please answer this!!!!! im begging !!! pleaseeeeeeee

Mathematics

1 answer:

svlad2 [7]3 years ago

3 0

This is really up to you. Also you Didn’t provide the assignment so this is impossible to answer, I can put anything in there. Just think about what you did and answer the questions yourself.

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PLEASE HELP Factor each expression. Show your work. <br> 2p^3 + 6p^2 + 3p + 9

Roman55 [17]

2p^3 + 6p^2 + 3p + 9....gonna have to factor by grouping

2p^2(p + 3) + 3(p + 3) =
(2p^2 + 3)(p + 3) <===

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4 years ago

Which is a true statement about the value of a credit report to lenders and borrowers?

Mars2501 [29]

Answer:

Step-by-step explanation:

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3 years ago

John's grade increased from a 77 to an 85. What is the approximate percent increase of John's grade

pentagon [3]

Answer:

10.4 hope this help ;) 77 x 10.4

Step-by-step explanation

turn the 10.4 into .10 then multiply like this

77 x .10 =7.7

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3 years ago

Read 2 more answers

Find the measurement of arc ac whose inscribed angle is 62 degrees

DerKrebs [107]

This the concept of circumference of circle. The arc length will be given by:
C=theta/360*pi*diameter
theta=62
diameter=d
thus the arc length will be:
C=62/360*π*d
C=0.54d

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3 years ago

A company produces packages of granola and has changed its recipe. It claims that the proportion of almonds in how is the approp

vova2212 [387]

Answer:

The correct answer is

$t = \frac{0.49-0.29}{\sqrt{\frac{(0.42)^2}{100} +}\frac{(0.29)^2}{100} }$

Step-by-step explanation:

To solve the question we note that the question involves a test statistic calculation given by

$t = \frac{x_1-x_2}{\sqrt{\frac{s_1^2}{n_1} +}\frac{s_2^2}{n_2} }$ Where

x₁ = Mean of sample 1

x₂ = Mean of sample 2

n₁ = Sample size of sample 1

n₂ = Sample size of sample 2

s₁ = Variance of sample 1

s₂ = Variance of sample 2

s₁ = ∑(x₁ - x₁')²/n₁, s₂ = ∑(x₂ - x₂')²/n₂

The test statistic is a variable that is derived from a given data sample and is applied in hypothesis testing. The test statistic measures the available data against the expected value from the null hypothesis

With the given data, we have

$t = \frac{0.49-0.29}{\sqrt{\frac{(0.42)^2}{100} +}\frac{(0.29)^2}{100} }$

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3 years ago