The present age of mother and her daughter respectively are; 40 and 10 years respectively.
<h3>How to Solve Algebra Word Problems?</h3>
Let x and y be the present age of mother and her daughter respectively.
Therefore;
x + y = 50
x = 50 − y .....(1)
After 20 years, mother's age will be twice her daughter's age at the time. Thus;
x + 20 = 2(y + 20)
x − 2y = 20 .....(2)
Plugging eq 1 into eq 2 gives us;
50 − y − 2y = 20
3y = 30
y = 10
Thus;
x = 50 − 10
x = 40
Thus, the present age of mother and her daughter is 40 and 10 years respectively.
Translation of the question into English is;
The sum of the present ages of mother and her daughter is 50 years. After 20 years, mother's age will be twice her daughter's age at the time. Find their present ages.
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Answer:
z^1+3z+2
Step-by-step explanation:
(z+1)(z+1)
Multiply each term in the first parenthesis by each term in the second parenthesis
Z x z+2z+z+2
Calculate the product
<u>z</u>^2 +2z+z+2
collect like terms
z^2+3z+2
2z+z
If a term doesnt have a coefficient it is considered that the coefficient is 1
2z+1z
(2+1)z
(2+1)z
3z
z^2+3z+2
It would be (3,10) because it is much bigger then the others
