Answer:
The approximate 90% confidence interval is;
70,244 to 70,732
Step-by-step explanation:
Here, we want to calculate the approximate 90% C.I for the situation
Mathematically;
CI = mean ± (z * SD)/√n
From the question;
mean = 70,438
SD = 645.3
n = 30
we can get z from the CI table
90% CI is same as; 1.645 z-score
So , substituting these values;
CI = 70,438 ± ( 1.645 * 645.3)/√30
CI = 70,438 ± 194
So the CI = 70,438 -194 to 70,438 + 194
= 70,244 to 70,732
Answer:
a)%85,5
b)%92,2
Step-by-step explanation:
a) To determine the probability of getting a hand with at least one face, we need to calculate the probability of the hand without any face firstly.
Then, we need to deduct this value from the probability 1
The probability of the hand with at least one face is %85,5.
b)To determine the probability of a hand with at least one ace and face we will track the same road again.
Then, we need to deduct this value from the probability 1
The probability of the hand with at least one ace and one face is %92,2.
Answer:
It's a.
Step-by-step explanation:
(a - 2b)^2 + 8ab
= a^2 - 4ab + 4b^2 + 8ab
= a^2 + 4ab + 4b^2.
((a + 2b)^2 = a^2 + 4ab + 4b^2.
Answer:
x = 5
Step-by-step explanation:
sin theta = opposite side / hypotenuse
sin 53 = 4/x
Multiply each side by x
x sin 53 = 4/x *x
x sin 53 = 4
Divide each side by sin 53
x sin 53 / sin 53 = 4 / sin 53
x = 4 /sin 53
x = 5.008542633
To the nearest whole number
x = 5
