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natita [175]
3 years ago
15

At-57 °C and 1 atm, carbon dioxide is in which phase? View Available Hint(s) Phase diagrams for water (Figure 1)and carbon dioxi

de (Figure 2)are given here for your reference O gas O liquid O solid O supercritical fluid solid-liquid equilibrium O liquid-gas equilibriunm O solid-gas equilibrium O solid-liquid-gas equilibrium Submit incorrect; Try Again; 3 attempts remaining On the diagram for carbon dioxide, fnd 1 atm on the pressure axis and-57 degrees on the temperature axis. Find where these values intersect, then read which phases are present. Figure 2 of 2 Part D Phase diagram for CO 73 At 10 C and 2 atm carbon dioxide is in the gas phase. From these conditions, how could the gaseous C02 be converted into liquid CO2? View Available Hint(s) Liquid Solid O O O O Increase the temperature. Decrease the temperature. Increase the pressure. Decroase the prossure. 5.2 Gas -78-57 0 31 Temperature (C) Submit

Chemistry
1 answer:
goblinko [34]3 years ago
4 0

Answer:

Gas

Increase the pressure

Explanation:

Let's refer to the attached phase diagram for CO₂ (not to scale).

<em>At -57 °C and 1 atm, carbon dioxide is in which phase?</em>

If we look at the intersection between -57°C and 1 atm, we can see that CO₂ is in the gas phase.

<em>At 10°C and 2 atm carbon dioxide is in the gas phase. From these conditions, how could the gaseous CO₂ be converted into liquid CO₂?</em>

Since at 10°C and 2 atm carbon dioxide is below the triple point, the only way to convert it into liquid is by increasing the pressure (moving up in the vertical direction).

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bagirrra123 [75]

Answer:

true

Explanation:

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3 0
3 years ago
What is the scientific term for the curved shape that results? guatured cyclinder
AnnyKZ [126]

Answer:

Curvature

Explanation:

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4 0
3 years ago
When benzene (c6h6) reacts with bromine (br2) bromobenzene(c6h5br) is obtained: c6h6 + br2 → c6h5br + hbr what is the theoretica
saveliy_v [14]

Answer A) : We have to calculate the number of moles of Benzene involved in the reaction,

30 g / 78 moles of benzene = 0.384 moles


For bromine it will be the same process,

65 g / 159.8 moles = 0.406 moles


By observing the reaction given above we can say that the reaction ratio of bromine and benzene is 1 : 1


We need to find the mass of bromobenzene,

which should be, 6(12) + 5 (1)+ 79.90 = 156.9 g/mol


So, the mass of bromobenzene will be 156.9 g/mol X 0.3846 mol = 60.343 g


Hence the theoretical yield will be 60.34 g


Answer B) : To calculate the actual yield we have to divide it with theoretical yield.


(56.7g / 60.343 g ) X100% = 93.96 %


Here, we can say that we got 93.96 % of actual yield.


As we know it is impossible to get 100% yield in any reaction.

3 0
3 years ago
Which of the following pairs of reactants is not correctly listed with its product solution? A. Strong base-strong acid reactant
alexandr1967 [171]

Answer: Option B

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HCl + NaOH —> NaCl + H2O

From the equation obtained, The salt ( NaCl) obtained is a normal salt which is neutral.

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3 years ago
Substances that cannot be separated and found on a periodic table
GaryK [48]

Substances that cannot be separated and found on a periodic table are elements.


4 0
3 years ago
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