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natita [175]
3 years ago
15

At-57 °C and 1 atm, carbon dioxide is in which phase? View Available Hint(s) Phase diagrams for water (Figure 1)and carbon dioxi

de (Figure 2)are given here for your reference O gas O liquid O solid O supercritical fluid solid-liquid equilibrium O liquid-gas equilibriunm O solid-gas equilibrium O solid-liquid-gas equilibrium Submit incorrect; Try Again; 3 attempts remaining On the diagram for carbon dioxide, fnd 1 atm on the pressure axis and-57 degrees on the temperature axis. Find where these values intersect, then read which phases are present. Figure 2 of 2 Part D Phase diagram for CO 73 At 10 C and 2 atm carbon dioxide is in the gas phase. From these conditions, how could the gaseous C02 be converted into liquid CO2? View Available Hint(s) Liquid Solid O O O O Increase the temperature. Decrease the temperature. Increase the pressure. Decroase the prossure. 5.2 Gas -78-57 0 31 Temperature (C) Submit

Chemistry
1 answer:
goblinko [34]3 years ago
4 0

Answer:

Gas

Increase the pressure

Explanation:

Let's refer to the attached phase diagram for CO₂ (not to scale).

<em>At -57 °C and 1 atm, carbon dioxide is in which phase?</em>

If we look at the intersection between -57°C and 1 atm, we can see that CO₂ is in the gas phase.

<em>At 10°C and 2 atm carbon dioxide is in the gas phase. From these conditions, how could the gaseous CO₂ be converted into liquid CO₂?</em>

Since at 10°C and 2 atm carbon dioxide is below the triple point, the only way to convert it into liquid is by increasing the pressure (moving up in the vertical direction).

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LenKa [72]

0.50 is the answer on edge

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3 years ago
Determine the mass of CuSO4 • 5H20 that must be used to prepare 250mL of 2.01 M CuSO4(aq).
mario62 [17]

Given parameters:

Volume of CuSO₄ = 250mL

Concentration of CuSO₄ = 2.01M

Unknown:

Mass of CuSO₄.5H₂O = ?

To solve this problem, we must write the chemical relationship between both species.;

             CuSO₄.5H₂O  →   CuSO₄ + 5H₂O

Now that we know the expression, it is possible to solve for the unknown mass.

First find the number of moles of CuSO₄;

         Number of moles  = Concentration x Volume

Take 250mL to L so as to ensure uniformity of units;

           Volume  = 250 x 10⁻³L

  Input the parameters and solve for number of moles;

        Number of moles  = 250 x 10⁻³  x  2.01 = 0.5mol

From the equation;

             1 mole of CuSO₄ is produced from 1 mole of CuSO₄.5H₂O  

So  0.5 moles of CuSO₄ will be produced from 0.5 moles of CuSO₄.5H₂O

Now let us find the molar mass of CuSO₄.5H₂O = 63.6 + 32 + 4(16) + 5(2x1 + 16)  = 249.6g/mole

Mass of CuSO₄.5H₂O = number of moles x molar mass

                                      = 0.5 x 249.6

                                     = 124.8g

The mass of CuSO₄.5H₂O is 124.8g

5 0
3 years ago
The public is not yet able to purchase cars powered by hydrogen fuel cells because engineers have to determine how the cars perf
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Answer:

It’s B just did it

Explanation:

6 0
3 years ago
Sulfonation of benzene has the following mechanism: (1) 2 H2SO4 ⇌ H3O+ + HSO4− + SO3 [fast] (2) SO3 + C6H6 → H(C6H5+)SO3− [slow]
ziro4ka [17]

Question is incomplete, complete question is as follows :

Complete Question : .Sulfonation of benzene has the following mechanism:

(1) 2 H2SO4 ⇌ H3O+ + HSO4− + SO3

[fast]

(2) SO3 + C6H6 → H(C6H5+)SO3−

[slow]

(3) H(C6H5+)SO3− + HSO4− → C6H5SO3− + H2SO4

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(4) C6H5SO3− + H3O+ → C6H5SO3H + H2O

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write the overall rate law for the initial rate of the reaction as a fraction.

Rate=k(________/_________)

Answer:

The overall rate law for the initial reaction is = k_{overall} [H_{2}SO_{4}]^{2} [C_{6}H_{6}]

Explanation :

Frist of all, all the common terms are cancelled out and written the overall reaction.

As we know that the rate depednant step is the slowest step of the reaction, rate law is :

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But the problem is that SO3 cannot be written in the overall rate law because it is an intermediate.

Rate law for synthesis of S03 is as follows :

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Hence when we substitute equation 2 in equation one,

                   Rate comes out to be =  k_{overall} [H_{2}SO_{4}]^{2} [C_{6}H_{6}]

6 0
2 years ago
28.7 l of propane, c3h8, are consumed in a combustion reaction. how many grams of water are produced?
lora16 [44]
The chemical reaction would be:

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For this case, we assume that gas is ideal thus in every 1 mol the volume would be 22.41 L. We calculate as follows:

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