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Len [333]
3 years ago
15

Cumene (isopropylbenzene) is a relatively inexpensive commercially available starting material. Show how you could prepare m-iso

propylnitrobenzene from cumene.

Chemistry
1 answer:
mafiozo [28]3 years ago
6 0

Answer:

Nitration is a general chemical process for the introduction of a nitro group into a chemical compound through a chemical reaction.

Aromatic nitration occurs with aromatic compounds thanks to an aromatic electrophilic substitution mechanism that includes the attack of an electron-rich benzene ring by the nitronium ion.

Explanation:

<h3> Reaction mechanism </h3>

Cumene reacts with concentrated and hot nitric acid giving

m- isopropylnitrobenzene. The reaction has two drawbacks: it is slow and also the concentrated and hot nitric acid can oxidize any organic compound by an explosive reaction. A safer procedure is to use a mixture of nitric acid and sulfuric acid. Sulfuric acid acts as a catalyst, allowing the reaction to take place more quickly and at lower temperatures.

Sulfuric acid reacts with nitric acid generating nitronium ion (NO2 +), which is the electrophile of the aromatic electrophilic substitution reaction.

The nitronium ion reacts with cumene forming the sigma complex that loses a proton that is trapped by the bisulfate ion to give rise to m-isopropylnitrobenzene.

Nitration selectivity can be found by examining ring substituents and the effect they have on the reaction rate of this aromatic electrophilic substitution. Deactivation groups such as other nitro groups have a withdrawal effect of the electron pair that deactivates the reaction (creating difficulty in the formation of polynitrated products) and directs the electrophilic nitronium ion to attack the aromatic meta position.

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Answer:

milky way

Explanation:

3 0
3 years ago
How many moles of Al would be produced from 20 moles of Al2O3?<br> 2Al2O3<br> -&gt;<br> 4A1 + 302
Evgesh-ka [11]
<h3>Answer:</h3>

\displaystyle 40 \ mol \ Al

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2Al₂O₃ → 4Al + 3O₂

[Given] 20 mol Al₂O₃

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Al₂O₃ → 4 mol Al

<u>Step 3: Stoich</u>

  1. [DA] Set up:                                                                                                     \displaystyle 20 \ mol \ Al_2O_3(\frac{4 \ mol \ Al}{2 \ mol \ Al_2O_3})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 40 \ mol \ Al

<u>Step 4:Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

Since our final answer already has 1 sig fig, there is no need to round.

4 0
3 years ago
How many significant figures are in the mass 3.0047 g?
Rudik [331]

Answer:

5 significant figures

5 0
3 years ago
Given that nitrogen forms three bonds with hydrogen to make <img src="https://tex.z-dn.net/?f=NH_%7B3%7D" id="TexFormula1" title
lbvjy [14]

Answer:

Three hydrogen atoms to form PH₃.

Explanation:

Hello!

In this case, since the elements belonging to the nitrogen family (N, P, As, Sb and Bi) show five valence electrons, because there are five electrons at their outer shell, it is clear that if phosphorous bonds with hydrogen, it is going to require the same amount of oxygen atoms (3) because elements having five valence electrons need 3 bonds in order to attain the octet (5+3=8).

Therefore the compound would be:

PH_3

Which is phosphine.

Best regards!

3 0
3 years ago
Please help!! 20 points!! Posted this previously and forgot to change it to 20 points but it is now
spayn [35]

Answer:

0.571 mol

Explanation:

Given data:

Number of moles of NaHCO₃ = 0.571 mol

Number of moles of CO₂ produced = ?

Solution:

Chemical equation:

NaHCO₃ + C₃H₆O₃   →     CO₂  + C₃H₅NaO₃ + H₂O

Now we will compare the moles of CO₂ with NaHCO₃ from balance chemical equation.

                             NaHCO₃          :            CO₂

                                    1                :               1

                                 0.571            :            0.571

So number of moles of CO₂  produced are 0.571.

3 0
3 years ago
Read 2 more answers
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