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Ket [755]
3 years ago
14

A bag contains 5 blue marbles, 6 red marbles, and 9 green marbles. Two marbles are drawn at random. What is the probability of f

irst drawing a blue marble and then, without replacing it, drawing a red marble?
A.9/20
B.3/38
C.1/19
D.11/20
Mathematics
1 answer:
pentagon [3]3 years ago
7 0
First: 5/20
second: 6/19

5/20 x 6/19 = 30/380 = 15/190 = 3/38. The answer is B
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Can someone help me with this please!
Vinil7 [7]

Answer:

This is really easy, take away all 1s and multiplication sign.

Step-by-step explanation:

And then it means 25=25

3 0
3 years ago
Use the estimates to help you choose each correct answer. 14.8(20.7) = Estimate: 15(20) = 300 1.1(9.8) = Estimate: 1(10) = 10 72
lara31 [8.8K]

Answer:

1st 306.36 2nd 10.78 3rd 355.25

Step-by-step explanation:

bc i just skipped and it showed me the answers

6 0
4 years ago
Read 2 more answers
PLEASE ANSWER + BRAINLIEST!!<br><br> Factor completely.<br><br> 4k - 20k^9 =<br><br> 3b^2 - 108 =
Neporo4naja [7]
4k-20k^9=4k(1-5k^8)=4k\left[1^2-(k^4\sqrt5)^2\right]\\\\=4k(1-k^4\sqrt5)(1+k^4\sqrt5)=4k\left[1^2-(k^2\sqrt[4]5)^2\right](1+k^4\sqrt5)\\\\=4k(1-k^2\sqrt[4]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k\left[1^2-(k\sqrt[8]5)^2\right](1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k(1-k\sqrt[8]5)(1+k\sqrt[8]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)

3b^2-108=3(b^2-36)=3(b^2-6^2)=3(b-6)(b+6)

Used:\ (a-b)(a+b)=a^2-b^2
7 0
3 years ago
The expression -5p + 20 factored is<br> factor out the coefficient of the variable
krek1111 [17]

Answer: -5(p-4)

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6 0
3 years ago
Please help me solve this.
Vlada [557]

Answer:

<h2>I think that is a FORMULA.</h2>

it can't be solved if we don't know the values of atleast one of the x and y.

Hope this helps.

Good luck ✅.

8 0
2 years ago
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