Answer:
- Positive at (-9, 2)
- Negative at ( -oo, -9) or (2, + oo)
Step-by-step explanation:
<u>Given function</u>
<u>Getting zero's</u>
- -2x^2 - 14x + 36 = 0
- x^2 + 7x - 18 = 0
- x = ( -7 ± √(49 +72))/2 = ( -7 ± 11)/2
- x = - 9 and x = 2
<u>As the x^2 has negative coefficient, the function is positive between -9 and 2</u>
<u>And it is negative at:</u>
- x < -9 and
- x > 2
- or
- ( -oo, -9) or (2, + oo)
Answer:
Hey there!
These would also be acute angles.
Let me know if this helps :)
152700 is answer. Try to do these problems on paper then you can see where you went wrong . also try to do the actual question
I cant help you on this if there is no coefficients.
AB = QR
BC = PR
CR = PQ
<A = <Q = 60
<B = <R = 90
<C = <P = 30