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3 years ago

Help it’s algebra 2!! asap plzz

Mathematics

1 answer:

Ostrovityanka [42]3 years ago

3 0

(x+3)(x-1/4)=x^2+11/4-3/4

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If the triangle is not right-angled, and there is not a matching pair, you will need the _____________ Rule.

nekit [7.7K]

Answer:

Cosine

Step-by-step explanation:

If the triangle is not right-angled, and there is not a matching pair, you will need the Cosine Rule..

and the formula used will be: $a^2 = b^2 + c^2 - 2 b c cos A$

In the opposite case if the triangle is not right-angled, and there is a matching pair, you will need the Sine Rule..

3 0

4 years ago

Instructions

S_A_V [24]

The theoretical probability of getting two tails on two coin tosses is 0.25.

<h3>How to calculate the probability?</h3>

The theoretical probability is the ratio of the number of favorable outcomes to the number of possible outcomes. Given a coin is tossed twice.

We have to find the theoretical probability of tossing two tails. The probability of getting tails on the toss of a coin is 1/2 0r 0.5.

Therefore, the probability of getting two tails on two coin tosses is 0.5 × 0.5 or 0.25.

The theoretical probability that a coin toss results in two heads showing is 0.25.

Learn more about probability on:

brainly.com/question/24756209

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7 0

2 years ago

MATH help please! needed asap

Marina CMI [18]

This is simple. a rectangle is formed by all of the coordinates listed and shown above.

5 0

3 years ago

Consider the matrix <img src="https://tex.z-dn.net/?f=A_%7B4x4%7D%2C%20det%28A%29%20%3D%20-2" id="TexFormula1" title="A_{4x4}, d

Lerok [7]

We found a counterexample, so the statement is false.

<h3>Is the statement true?</h3>

Let's use the matrix:

$\left[\begin{array}{cccc}-2&0&0&0\\0&1&0&0\\0&0&1&0\\ 0&0&0&1 \end{array}\right]$

This is a 4x4 matrix with determinant equal to -2.

The inverse matrix is:

$\left[\begin{array}{cccc}1/2&0&0&0\\0&-1&0&0\\0&0&-1&0\\ 0&0&0&-1 \end{array}\right]$

If we multiply it by 2, we get:

$\left[\begin{array}{cccc}1&0&0&0\\0&-2&0&0\\0&0&-2&0\\ 0&0&0&-2 \end{array}\right]$

The adjoint of that is the original matrix, actually:

$\left[\begin{array}{cccc}-2&0&0&0\\0&1&0&0\\0&0&1&0\\ 0&0&0&1 \end{array}\right]$

Which we already know, has a determinant of -2.

So the statement is false, as we found a counterexample.

If you want to learn more about matrices:

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7 0

2 years ago

Factor completely 50 a^2 b^5 - 35 a^4 b^3 + 5 a^3 b^4

maw [93]

Answer:

$5a^2b^3(-7a^2+ab+10b^2)$

Step-by-step explanation:

Factor $50 a^2 b^5 - 35 a^4 b^3 + 5 a^3 b^4$

$−35a^4b^3+5a^3b^4+50a^2b^5$

= $5a^2b^3(-7a^2+ab+10b^2)$

3 0

3 years ago