Im not sure but i think your m is(-2,0) and your b is (6,0)
Answer:
b. 0.25
c. 0.05
d. 0.05
e. 0.25
Step-by-step explanation:
if the waiting time x follows a uniformly distribution from zero to 20, the probability that a passenger waits exactly x minutes P(x) can be calculated as:

Where a and b are the limits of the distribution and x is a value between a and b. Additionally the probability that a passenger waits x minutes or less P(X<x) is equal to:

Then, the probability that a randomly selected passenger will wait:
b. Between 5 and 10 minutes.

c. Exactly 7.5922 minutes

d. Exactly 5 minutes

e. Between 15 and 25 minutes, taking into account that 25 is bigger than 20, the probability that a passenger will wait between 15 and 25 minutes is equal to the probability that a passenger will wait between 15 and 20 minutes. So:

10(1+3.5%)=10.35 increased by.35 in a year
Answer:
8.7 so either 8 or 9 tenth of a year
Step-by-step explanation:
<em>Is it compounded per month? I assume</em>
1. Compound interest formula
FV = PV(1+r/100k)^kn
FV is the future value,
PV is the present value,
n is the number of years,
k is the number of compounding periods per year
r% is the nominal annual rate of interest
2. Plug in numbers
3550 = 2400(1+4.6/100*12)^12*n
71/48 = (6023/6000)^12n
12n = logBase(6023/6000)*(71/48)
n = answer/12
n ≈ 8.70