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nalin [4]
3 years ago
14

Charles sells computer hardware for a computer manufacturer. He is paid 4% for

Mathematics
1 answer:
valentinak56 [21]3 years ago
3 0
Call me 205 579 7799 if u need help because this stuff is easy
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Find the difference between the polynomials:<br><br><br><br>–3x+x^3–2x^2 and 4x^3–2x^2–4x
Andrews [41]

x-3x^3

Step-by-step explanation:

just pretend they are in parentheses and open them

3 0
4 years ago
How to solve this limit?
wlad13 [49]
(2x^2/(1-x^2)) + 3^(1/x)  for the first half you can simply divide all terms by the highest power of x to get:

2/(1/x^2-1)  as x approaches infinity you have 2/-1=-2

For the second part the exponent approaches zero as x approaches infinity and anything raised to the zero power is equal to 1 so you have:

-2+1=-1

So the limit as x approaches infinity is -1.
3 0
3 years ago
Read 2 more answers
When solving negative one over eight (x + 35) = −7, what is the correct sequence of operations?
SashulF [63]

Step-by-step explanation:

assuming the first part is -1/8th, you would want to first add 1/8, to attempt to isolate the x. you now have x+35 = -6 7/8. add 35, and you get x= 28 1/8

4 0
3 years ago
Write the equation of a line that is
il63 [147K]

Answer:

Y= 3x-7

Step-by-step explanation:

Since the line is parallel , the slope is same i.e. 3 .

now the equation should be y= Mx + b where m is the slope and c is the y-intercept

plugging the value of m=3 and ( 3,2) into the equation

2= 3(3) + c

2= 9+ c

c= -7

hence the equation of the line is y=3x-7

8 0
3 years ago
A giant pie is created in an attempt to break a world record for baking. The pie is shown below: A circle is shown with a centra
lisabon 2012 [21]

Answer:

a. 22.08 ft^{2

Step-by-step explanation:

d = diameter = 15ft; r = (1/2)d = 7.5ft; A=area

So, A = (π) × r^{2}

A = (π) × (7.5ft)^{2}

A = (π) × (56.25ft^{2})

The entire circle is 360°, so 45 is \frac{1}{8}.

A(slice) = (\frac{56.25}{8}) × ft^{2} π

A(slice) = 7.03 × (π) × ft^{2}

(Please vote me Brainliest if this helped!)

4 0
3 years ago
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