2 answers:
Answer:
4v^2y^5
-----------------------
(3u^4+5v^2)
Step-by-step explanation:
We can factor out a 2 v^2 out of the numerator and denominator
8v^4y^5 = (2v^2) *4v^2y^5
6u^4v^2 + 10 v^4 = 2v^2 (3u^4+5v^2)
So
8v^4y^5
-----------------
6u^4v^2 + 10 v^4
becomes
(2v^2) *4v^2y^5
-----------------------
2v^2 (3u^4+5v^2)
Canceling 2v^2
4v^2y^5
-----------------------
(3u^4+5v^2)

your final answer
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Answer:
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Step-by-step explanation:
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Answer:
B is the correct answer accordingly to your question
Where’s the picture? Or link?
Answer:
![( \sqrt[4]{10} ) ^{3x}](https://tex.z-dn.net/?f=%28%20%5Csqrt%5B4%5D%7B10%7D%20%29%20%5E%7B3x%7D%20)