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HACTEHA [7]
3 years ago
5

Please help Simplify

Mathematics
2 answers:
marshall27 [118]3 years ago
6 0

Answer:

4v^2y^5

-----------------------

(3u^4+5v^2)

Step-by-step explanation:

We can factor out a 2 v^2 out of the numerator and denominator

8v^4y^5  = (2v^2) *4v^2y^5

6u^4v^2 + 10 v^4 = 2v^2 (3u^4+5v^2)

So

8v^4y^5

-----------------

6u^4v^2 + 10 v^4

becomes

(2v^2) *4v^2y^5

-----------------------

2v^2 (3u^4+5v^2)

Canceling 2v^2

4v^2y^5

-----------------------

(3u^4+5v^2)

pogonyaev3 years ago
4 0

\frac{4v {}^{2} {y}^{5}  }{3 {v}^{4}  + 5v {}^{2} }

your final answer

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I can’t figure out this answer I’ve gotten so many and it seems non of them work
Mandarinka [93]

The quotient is 0.20125.

Solution:

Divide .03220 by .16

This can be written as

$\frac{\cdot 03220}{\cdot 16}

To divide this, we first remove the decimal term.

To remove decimal in denominator multiply and divide by 100.

$\frac{\cdot 03220}{\cdot 16}\times \frac{100}{100}=\frac{3.22}{16}

Now, divide 3.22 by 16.

The quotient is 0.20125.

The image of the long division is attached below.

6 0
3 years ago
Which of the following is not an equation of a simple, even polynomial function? y = | x | y = x2 y = x3 y = -x2
den301095 [7]

Answer:

  • y = | x |
  • y = x^3

Step-by-step explanation:

The absolute value function prevents the expression from being a polynomial. The degree of 3 in y^3 is an odd number so that polynomial function will not be even.

5 0
3 years ago
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Find the sum of the first 25 terms of the arithmetic sequnce 17,22,27,32.37
ANTONII [103]

Answer:

Step-by-step explanation:

This sequence is adding 5 so

17 22 27 32 37 42 47 52 57 62 67 72 77 82 87 92 97 102 107 112 117 122 127 132 137 = 1925

6 0
3 years ago
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WIL GIVE BRAINLIEST<br> Focus (- 2, - 3) Directrix x = 6
aliina [53]

Answer:

Here's ya answer!

(

y

+

3

)

2

=

−

6

(

x

−

7

2

)

Sorry its upside down, but good luck on that test!

4 0
3 years ago
I need answer please
ycow [4]

Answer:

2

Step-by-step explanation:

Trigonometric identities:

\sin^{2} (x)  +  { \cos}^{2} (x) = 1 \\  {\cos}^{2} (x) = 1 -  { \sin}^{2} (x) \\   { \sin }^{2} x = 1 - {\cos}^{2} (x) \:

Replace into the equation

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Remove roots and simply

=  \frac{ \sin(x) }{ \sin(x) }  +   \frac{ \cos(x) }{ \cos(x) }  \\  \\  = 1 + 1 \\  = 2

5 0
3 years ago
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