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Free_Kalibri [48]
3 years ago
8

Solve for x and y: 3x/5+y/2=13/10 and .5y+0.04x=2.42

Mathematics
1 answer:
Eva8 [605]3 years ago
3 0
3 x / 5 + y / 2 = 13/10   / * 10
0.5 y + 0.04 x = 2.42    / * 100
---------------------------------------
6 x + 5 y = 13  / * ( - 10 )
4 x + 50 y = 242
-------------------------------
- 60 x - 50 y = - 130
+
    4 x + 50 y  =  242
-----------------------------
- 56 x = 112
x = 112 : ( - 56 ) = - 2
-12 + 5 y = 13
5 y = 25
y = 25 : 5 = 5
Answer:
x = -2,  y = 5.
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Step-by-step explanation:

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What is the radius of a circle given by the equation x2 + y2 – 2x + 8y – 47= 0? radius = units
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ANSWER

The radius is 8

EXPLANATION

We were given,

{x}^{2}  +  {y}^{2}  - 2x + 8y - 47 = 0




We rewrite the above equation to obtain,

{x}^{2}  - 2x \:  \:  \:  \:  +  {y}^{2}  + 8y \:  \:  \:  \:  = 47


We now add half the square of the coefficient of
x \: and \: y
to both sides of the equation to get,


{x}^{2}  - 2x  + ( - 1) ^{2}  +  {y}^{2}  + 8y  +  {(4)}^{2} = 47 + ( - 1) ^{2}  +   {4}^{2}



We now got two perfect squares on the left hand side of the equation,


(x - 1)^{2}   +  {(y + 4)}^{2} = 47 + 1 +   16


(x - 1)^{2}   +  {(y + 4)}^{2} =64



(x - 1)^{2}   +  {(y + 4)}^{2}  =  {8}^{2}



By comparing to the general formula of the circle,


{(x - a)}^{2}  +  {(y - b)}^{2}  =  {r}^{2}


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