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lozanna [386]
3 years ago
9

What is 3 2/3+2.3 the 2.3 is a repeating decimal

Mathematics
2 answers:
tester [92]3 years ago
4 0

Answer:

5.96 with the repeating sign over the 6

Step-by-step explanation:

viktelen [127]3 years ago
4 0

Answer:

6.

Step-by-step explanation:

Convert the decimal to a fraction:

2.33333....  = 2 1/3, so it is:

3 2/3 + 2 1/3

= 3 + 2 + 2/3 + 1/3

= 3 + 2 + 1

= 6.

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If m∠1 equals (4x + 2) and m∠3 equals (5x − 25), what is the value of x?
vitfil [10]

Step-by-step explanation: the answer is x = 1/2

7 0
3 years ago
Help me!!!
nadya68 [22]

Step-by-step explanation:

You would start by using one of the equations to find y with x in the equation. You want to pick the easier one. I picked this one because it was evenly divisible.

5x+5y=50

5x=-5y+50

x=-y+10

Then you what to plug that in to the second equation and solve for y.

3(-y+10)+4y=32

-3y+30+4y=32

-3y+4y=2

y=2 (because you combined like terms)

Then you would plug back into the first equation and solve for x.

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8 0
4 years ago
What is the circumference of a circle with a radius of 5 feet? Use T=3.14<br> test
ipn [44]

Answer:

c=31.42

Step-by-step explanation:

It would be greatly appreciated if you gave me brainlest.

7 0
3 years ago
30 minus 5 times 4 plus 2 is what? im so bad at homework. first person gets ten points.
Yuri [45]
30-5*4+2
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6 0
3 years ago
Read 2 more answers
Is domain of f(x,y) = 1 + (4 -y^2)^1/2 open, closed or neither<br><br> is it bounded or unbounded?
omeli [17]

Answer:

Closed and Bounded.

Step-by-step explanation:

Hi there!

1) Let's start by finding the values in which the function is defined. Remember that this can be rewritten:

f(x,y) = 1 + (4 -y^2)^{\frac{1}{2}} \:id\:est\:f(x,y)=1+\sqrt{(4 -y^2)}

Since every quadratic root are defined for values \geq 0  then, this help us to understand that we need calculate what interval this Domain is:

4-y^{2} \geq 0\\4-y^{2}-4\geq -4\\-y^{2}\geq-4 \\y^{2}\leq4\\-2\leq y\leq 2

D=[-2,2]

2) Graphically speaking, the domain is closed. For the values -2 and 2 are included, and bounded.

Bounded functions have all of their points contained by some circle origin centered. Check it out below.

6 0
4 years ago
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