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3 years ago

Answer the question please.

Mathematics

1 answer:

Mariulka [41]3 years ago

6 0

8/5x = 1

1.6x = 1

Work:

Add 7/3x and 1/3x to make 8/3x. Equation: 8/3x = 1 + 5/3x

Divide 8/3x by 5/3x, looks like 8 over 3 times 3 over 5. 3s cancel each other out, leaving 8/5x. Equation: 8/5x = 1

If needed to be simplified, 8/5 = 1.6.

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Express 72×12 in the exponential form

kobusy [5.1K]

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3 years ago

Find the equation of a line parallel to – 2y = –2 – 2x that passes through the<br> point (9,-9).

riadik2000 [5.3K]

Answer:

2y + 2x = 0

Step-by-step explanation:

First you have to find the slope of the line.

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2 years ago

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8 0

3 years ago

the length of a rectagle is 5 in longer than its width. if the perimeter of the rectangle is 58 in, find its length and width

dolphi86 [110]

Answer:

Length = 17 inches

Width = 12 inches

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Step-by-step explanation:

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As it is given that, the length of a rectangle is 5 in longer than its width and the perimeter of the rectangle is 58 in and we are to find the length and width of the rectangle. So,

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Let us assume the width of the rectangle as x inches and therefore, the length will be (x + 5) inches .

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Now, <u>According to the Question :</u>

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${\longrightarrow \qquad { \pmb{\frak {2 ( Length + Breadth )= Perimeter_{(Rectangle)} }}}}$

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${\longrightarrow \qquad { {\sf{2 ( x + 5 + x )= 58 }}}}$

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${\longrightarrow \qquad { {\sf{2 ( 2x + 5 )= 58 }}}}$

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${\longrightarrow \qquad { {\sf{ 4x + 10= 58 }}}}$

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${\longrightarrow \qquad { {\sf{ 4x = 58 - 10}}}}$

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${\longrightarrow \qquad { {\sf{ 4x = 48}}}}$

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${\longrightarrow \qquad { {\sf{ x = \dfrac{48}{4} }}}}$

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${\longrightarrow \qquad{ \underline{ \boxed { \pmb{\mathfrak {x = 12}} }}} }\: \: \bigstar$

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Therefore,

The width of the rectangle is 12 inches .

⠀

Now, We are to find the length of the rectangle:

${\longrightarrow \qquad{ { \frak{\pmb{Length = x + 5 }}}}}$

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${\longrightarrow \qquad{ { \frak{\pmb{Length = 12 + 5 }}}}}$

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${\longrightarrow \qquad{ { \frak{\pmb{Length = 17}}}}}$

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Therefore,

The length of the rectangle is 17 inches .

⠀

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