ΔJKL, sin(JLK)=JK/KL=3/6=0.5
<JKL=30deg.
cos(JLK)=JL/KL
JL=KL*cos(JLK)=6cos(30deg.)
<JLK + <JLM = <MLK
30 + <JLM = 61
<JLM=31deg
in ΔMJL
tan(JLM)=JM/JL
JM=JL*tan(JLM)
=6cos(30deg.)*tan(31deg)
=3.12
Answer:
It is called this
Step-by-step explanation:
Since the three points are all on the same line, they are called collinear points.
Answer:


Step-by-step explanation:
Absolute Value Inequality entered :
|y+2|>6
Step by step solution :
Step 1: Rearrange this Absolute Value Inequality
Absolute value inequalitiy entered
|y+2| > 6
Step 2: Clear the Absolute Value Bars
Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.
The Absolute Value term is |y+2|
For the Negative case we'll use -(y+2)
For the Positive case we'll use (y+2)
Step 3: Solve the Negative Case
-(y+2) > 6
Multiply
-y-2 > 6
Rearrange and Add up
-y > 8
Multiply both sides by (-1)
Remember to flip the inequality sign
y < -8
Which is the solution for the Negative Case
Step 4: Solve the Positive Case
(y+2) > 6
Rearrange and Add up
y > 4
Which is the solution for the Positive Case
Step 5:
Wrap up the solution
y < -8
y > 4
Solutions in Interval Notation
(-∞,-8)
(4,+∞)
Solutions on the Number Line
Two solutions were found :
y > 4
y < -8
Answer:
h= x/ x+4
Step-by-step explanation:
Move all terms to the left side and set equal to zero, Then set each factor equal to zero.
6x^2 + 4(x^2 - 1) =
6x^2 + 4x^2 - 4 =
10x^2 - 4 <===