Answer:
x⁰ = 45⁰
Step-by-step explanation:
As it is given that the 2 sides of a triangle are equal, then it is an isosceles triangle.
Now, by applying the Triangle Sum Property,
x⁰ + 90⁰ + 45⁰ = 180⁰
x⁰ = 180⁰ - 135⁰
x⁰ = 45⁰
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em> </em><em>:</em><em>)</em>
Hope this helps with the answer to your question:) (sorry I didn't know how to do question 30)
Answer:
the nth term of the sequence is 
Step-by-step explanation:
Given : An arithmetic sequence begins as follows: 
To find : Which of the following gives the definition of its nth term?
Solution :
The nth term of the A.P is 
The first term is 
The common difference is 

Substitute in the formula,



Therefore, the nth term of the sequence is 
Answer: True.
Step-by-step explanation:
Answer:
Step-by-step explanation:
a) Yes.

b) Yes

c) Yes

d) No
