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aev [14]
3 years ago
5

Hikers spent the following amounts of time (in minutes) to complete a nature hike:48, 46, 52, 57, 58, 52, 61, 56.

Mathematics
2 answers:
Solnce55 [7]3 years ago
8 0
For A for the mean just add them all up which would be which is 430 and divide by the number of numbers there is so 430 divided by 8 = 53.75 and the median order them from least to greatest and find the one in the middle which is 52 and 56 when there's two just add them and then divide it by 2 which is 54

Hope this helped :)
DiKsa [7]3 years ago
3 0

Answer:

Step-by-step explanation:

Given that hikers spent the following amounts of time (in minutes) to complete a nature hike:48, 46, 52, 57, 58, 52, 61, 56.

Mean = sum/no of items = \frac{430}{8} =53.75

In ascending order this becomes

46, 48, 52, 52, 56, 57, 58, 61

Median is average of middle items

=\frac{52+56}{2} =54

Here mean is less than median this implies there are more entries above the mean.  i.e. skewed not symmetrical. For symmetrical distributions mean and median would be equal

c) If 92 is added to this data entry median becomes 56 but mean becomes

\frac{430+92}{9} \\=58 while median increases by 4.75

d) Median is better because it is not affected by outliers i.e. extreme values added to the set

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Answer:

The probability that a random selected student score is greater than 76 is \\ P(x>76) = 0.99865.

Step-by-step explanation:

The Normally distributed data are described by the normal distribution. This distribution is determined by two <em>parameters</em>, the <em>population mean</em> \\ \mu and the <em>population standard deviation</em> \\ \sigma.

To determine probabilities for the normal distribution, we can use <em>the standard normal distribution</em>, whose parameters' values are \\ \mu = 0 and \\ \sigma = 1. However, we need to "transform" the raw score, in this case <em>x</em> = 76, to a z-score. To achieve this we use the next formula:

\\ z = \frac{x - \mu}{\sigma} [1]

And for the latter, we have all the required information to obtain <em>z</em>. With this, we obtain a value that represent the distance from the population mean in standard deviations units.

<h3>The probability that a randomly selected student score is greater than 76</h3>

To obtain this probability, we can proceed as follows:

First: obtain the z-score for the raw score x = 76.

We know that:

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\\ \sigma = 3

\\ x = 76

From equation [1], we have:

\\ z = \frac{76 - 85}{3}

Then

\\ z = \frac{-9}{3}

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Second: Interpretation of the previous result.

In this case, the value is <em>three</em> (3) <em>standard deviations</em> <em>below</em> the population mean. In other words, the standard value for x = 76 is z = -3. So, we need to find P(x>76) or P(x>-3).

With this value of \\ z = -3, we can obtain this probability consulting <em>the cumulative standard normal distribution, </em>available in any Statistics book or on the internet.

Third: Determination of the probability P(x>76) or P(x>-3).

Most of the time, the values for the <em>cumulative standard normal distribution</em> are for positive values of z. Fortunately, since the normal distributions are <em>symmetrical</em>, we can find the probability of a negative z having into account that (for this case):

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Then

Consulting a <em>cumulative standard normal table</em>, we have that the cumulative probability for a value below than three (3) standard deviations is:

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Thus, "the probability that a random selected student score is greater than 76" for this case (that is, \\ \mu = 85 and \\ \sigma = 3) is \\ P(x>76) = P(z>-3) = P(z.

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<em>We can see below a graph showing this probability.</em>

As a complement note, we can also say that:

\\ P(z3)

\\ P(z3)

Which is the case for the probability below z = -3 [P(z<-3)], a very low probability (and a very small area at the left of the distribution).

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