Answer:
The amount that Lena will invest in fund B would be $4000.
Explanation:
Given information -
Amount invested in fund A - $6000
Return earned on fund A - 6%
Let us assume amount invested in fund B be x
Return earned on fund B - 1%
Return on both funds together - 4%
Let us assume the total amount of fund invested be ($6000 + x)
Now using simple equation , we will take out the value of x which is the amount invested in fund B -
$6000 X 6% + x X 1% = 4% ( $6000 + x )
= $360 + .01 x = $240 + .04 x
= $360 - $240 = .04 x - .01 x
$120 = .03 x
x = $120 / .03
= $4000.
Answer:
$79,800
Explanation:
Depreciation expense using the activity method = (actual hours of use in a given period / total estimated hours of use ) × ( Cost of asset - Salvage value)
(1500/10,000) × ($560,000 - $28,000) = $79,800
I hope my answer helps you.
Answer: Option (B) is correct.
Explanation:
Correct option: Decreasing marginal product.
Marginal product is the change in the level of output, when there will be an extra input employed in the production of a certain commodity.
So, Marginal Product = 
Where,
Q = Output
I = Input
Marginal product of 1st bag = 500
Marginal product of 2nd bag = 
= 300
Marginal product of 3rd bag = 
= 100
∴ From the above calculations, we can seen that as we employed one more bag of seeds as a result marginal product goes on diminishing.
Hence, Joan's production function exhibits decreasing marginal product.
Answer:
Price of One Bush is $ 23
Explanation:
Suppose
bushes = B
trees = T
According to given condition:
13B + 4T = 487 (Eq: 1)
6B + 2T = 232 (Eq: 2)
Multiplying (Eq: 2) by 2
12B + 4T = 464 (Eq: 3)
Substractign (Eq: 3) from (Eq: 1)
13B + 4T - (12B + 4T) = 487 - 464
13B + 4T - 12B - 4T = 23
B = 23
By putting value of B in (Eq: 1)
(13 x 23) + 4T = 487
299 + 4T = 487
4T = 487 - 299
4T = 188
T = 188 / 4
T = 47
Price of One Bush = B = 23
That statement is true
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