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Paladinen [302]
3 years ago
5

In which situation does physical activity move beyond the baseline level?

Physics
2 answers:
Reil [10]3 years ago
5 0
B is the correct answer

Ede4ka [16]3 years ago
3 0
B) jogging
Because that's constant and the others are, short, non moving and basic. 
So the only left out answer is B. Jogging.
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What is the definition of erosion
babunello [35]

Answer:

Erosion is the process of eroding or being eroded by wind, water, or other natural agents.

Explanation:

"the problem of soil erosion"

the gradual destruction or diminution of something.

"the erosion of support for the party"

are examples of how it could be used.

5 0
4 years ago
Read 2 more answers
The sizes of most of the cells our bodies are about A.1micrometer
Alekssandra [29.7K]

Answer:

1Mm

Explanation:

i think this one. so it is wrong then also dont be angry with me because iam trying to help u

5 0
3 years ago
Read 2 more answers
M=3000km v=25m/s what’s the momentum
valina [46]
<h3>Answer:</h3>

Momentum of the given body will be : 75000 Kg m/s

<h3>Explanation:</h3>

According to Newton's first law of motion, all bodies continue to be in the state of rest or motion unless an external force is applied on the body. We can use this in the case of momentum also

The formula of momentum is given by :

:\implies \sf\quad \sf \:  P = mv

Here, we are given the mass of the body ( m ) as 3000kg and the velocity of the body ( v ) as 25 m/s. On putting the values in the formula:

\begin{aligned}&:\implies \sf\quad \sf \:  P = mv \\& :\implies \sf\quad \sf \:  P = 3000 \times 25 \\ & :\implies \sf\quad \sf \:   \boxed{ \sf \: P = 75000kgm {s}^{ - 1} } \end{aligned}

Momentum is associated with the mass of the moving body and can be defined as the quantity of motion measured as a product of mass and velocity.

8 0
3 years ago
Which statement accurately describes the outer planets?
tiny-mole [99]
The outer planets have a high gravity due to their large size
6 0
3 years ago
Read 2 more answers
A person hits a tennis ball with a mass of 0.058 kg against a wall.
horrorfan [7]

Explanation:

Mass of the ball, m = 0.058 kg

Initial speed of the ball, u = 11 m/s

Final speed of the ball, v = -11 m/s (negative as it rebounds)

Time, t = 2.1 s

(a) Let F is the average force exerted on the wall. It is given by :

F=\dfrac{m(v-u)}{t}

F=\dfrac{0.058\times (11-(-11))}{2.1}

F = 0.607 N

(b) Area of wall, A=3\ m^2

Let P is the average pressure on that area. It is given by :

P=\dfrac{F}{A}

P=\dfrac{0.607\ N}{3\ m^2}

P = 0.202 Pa

Hence, this is the required solution.

8 0
3 years ago
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