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3 years ago

In which situation does physical activity move beyond the baseline level?

Physics

2 answers:

Reil [10]3 years ago

5 0

B is the correct answer

Ede4ka [16]3 years ago

3 0

B) jogging
Because that's constant and the others are, short, non moving and basic.
So the only left out answer is B. Jogging.

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Help with science for A P E X

eimsori [14]

Answer:

inertia

Explanation:

7 0

3 years ago

You are on a train that is traveling at 3.0 m/s along a level straight track. Very near and parallel to the track is a wall that

loris [4]

Questions Diagram is attached below

Answer:

$T=2.08s$

Explanation:

From the question we are told that:

Speed of Train $V=3.0m.s$

Angle $\theta=12\textdegree$

Height of window $h_w=0.90m$

Width of window $w_w=2.0m$

The Horizontal distance between B and A from Trigonometric Laws is mathematically given by

$b=\frac{0.9}{tan12}$

$b=4.23$

Therefore

Distance from A-A

$d_a=2.0+4.23$

$d_a=6.23$

Therefore

Time Required to travel trough d is mathematically given as

$T=\frac{d_a}{v}$

$T=\frac{6.23}{3}$

$T=2.08s$

5 0

3 years ago

Three individual point charges are placed at the following positions in the x-y plane:Q3= 5.0 nC at (x, y) = (0,0);Q2= -3.0 nC a

ozzi

Answer:

Explanation:

net force exerted on charge Q₃, exerted by charges Q₁and Q₂, will be zero

if net electric field due to charges Q₁ and Q₂ at origin is zero .

electric field due to Q₂

= 9 X 10⁹ X 3 x10⁹ / .04²

electric field due to Q₁

= 9 X 10⁹ X Q₁ / .02²

For equilibrium

9 X 10⁹ X Q₁ / .02² = 9 X 10⁹ X 3 x10⁻⁹ / .04²

Q₁ = 3 X10⁻⁹ x .02² / .04²

= 3 / 4 x 10⁻⁹

.75 x 10⁻⁹ C

8 0

3 years ago

Even though Alice visits the wishing well frequently and always tosses in a coin for good luck, none of her wishes have come tru

Lady_Fox [76]

Answer: 4.29 m/s

Explanation:

Given

Depth of the well, s = 8.23 m

Time taken to reach the well, t = 0.93 s

Speed of sound = 343 m/s

To solve this, we would be using one of l the laws of motion.

S = ut + 1/2gt², where

S = depth of the well

u = initial speed of toss

g = acceleration due to gravity

t = time taken to reach the well

We would then have

8.23 = 0.93 u + 1/2 * 9.8 * 0.93²

8.23 = 0.93 u + 4.9 * 0.8649

8.23 = 0.93 u + 4.23801

0.93 u = 8.23 - 4.23801

0.93 u = 3.99199

u = 3.99199 / 0.93

u = 4.29 m/s

Therefore, the initial speed of the coin is 4.29 m/s

3 0

4 years ago

You push a cart with mass 15 kg forward, giving it an acceleration of 3 m/s2

NARA [144]

Answer:

45 N

Explanation:

F= ma (ie force is found by multiplying the mass of the object by its accerelation)

thus, F = 15 X 3 = 45 N

8 0

3 years ago