Line Graph
Hope this is what you are looking for!
It's weird but technically correct to say that a radio wave can be considered a low-frequency light wave. Radio and light are both electromagnetic waves. The only difference is that radio waves have much much much longer wavelengths, and much much much lower frequencies, than light waves have. But they're both the same physical phenomenon.
However, a radio wave CAN'T also be considered to be a sound wave. These two things are as different as two waves can be.
-- Radio is an electromagnetic wave. Sound is a mechanical wave.
-- Radio waves travel more than 800 thousand times faster than sound waves do.
-- Radio waves are transverse waves. Sound waves are longitudinal waves.
-- Radio waves can travel through empty space. Sound waves need material stuff to travel through.
-- Radio waves can be detected by radio, TV, and microwave receivers. Sound waves can't.
-- Sound waves can be detected by our ears. Radio waves can't.
-- Sound waves can be generated by talking, or by hitting a frying pan with a spoon. Radio waves can't.
-- Radio waves can be generated by an alternating current flowing through an isolated wire. Sound waves can't.
Answer:
The magnitudes of the second force is ![Z = 129.9 N](https://tex.z-dn.net/?f=Z%20%3D%20129.9%20N)
The magnitudes of the resultant force is ![R = 256.047 N](https://tex.z-dn.net/?f=R%20%3D%20256.047%20N)
Explanation:
From the question we are told that
The force is ![F = 187 \ lb](https://tex.z-dn.net/?f=F%20%3D%20187%20%5C%20lb)
The angle made with second force ![\theta_o = 73 ^o 36' = 73 + \frac{36}{60} = 73.6^o](https://tex.z-dn.net/?f=%5Ctheta_o%20%3D%2073%20%5Eo%2036%27%20%3D%20%2073%20%2B%20%5Cfrac%7B36%7D%7B60%7D%20%20%3D%20%2073.6%5Eo)
The angle between the resultant force and the first force ![\theta _1 = 29 ^o 1 ' = 29 + \frac{1}{60} = 29.0167^o](https://tex.z-dn.net/?f=%5Ctheta%20_1%20%20%3D%2029%20%5Eo%201%20%27%20%3D%2029%20%2B%20%5Cfrac%7B1%7D%7B60%7D%20%20%3D%2029.0167%5Eo)
For us to solve problem we are going to assume that
The magnitude of the second force is Z N
The magnitude of the resultant force is R N
According to Sine rule
![\frac{F}{sin (\theta _o - \theta_1 } = \frac{Z}{\theta _1}](https://tex.z-dn.net/?f=%5Cfrac%7BF%7D%7Bsin%20%28%5Ctheta%20_o%20-%20%5Ctheta_1%20%7D%20%20%3D%20%5Cfrac%7BZ%7D%7B%5Ctheta%20_1%7D)
Substituting values
![Z = 129.9 N](https://tex.z-dn.net/?f=Z%20%3D%20129.9%20N)
According to cosine rule
![R = \sqrt{F ^2 + Z^2 + 2(F) (Z) cos (\theta _o) }](https://tex.z-dn.net/?f=R%20%3D%20%5Csqrt%7BF%20%5E2%20%2B%20Z%5E2%20%2B%202%28F%29%20%28Z%29%20cos%20%28%5Ctheta%20_o%29%20%7D)
Substituting values
![R = \sqrt{187^2 + 129.9 ^2 + 2 (187 ) (129.9) cos (73.6)}](https://tex.z-dn.net/?f=R%20%3D%20%5Csqrt%7B187%5E2%20%2B%20129.9%20%5E2%20%20%2B%202%20%28187%20%29%20%28129.9%29%20cos%20%2873.6%29%7D)
![R = 256.047 N](https://tex.z-dn.net/?f=R%20%3D%20256.047%20N)
<span>The answers are:
bulb, motor, buzzer and swtich.As seen in the picture attached,
The electric current leaves the battery passes through
the bulb. It then travels through the
motor, next through the
buzzer and finally passes through the
switch before returning to the battery.</span>
Your answer is C hope i helped
have a good day :)